How many moles of precipitate will be formed when 147.0 mL of 0.200 M NaBr is reacted with excess Pb(NO₃)₂ in the following chemical reaction? 2 NaBr (aq) + Pb(NO₃)₂ (aq) → PbBr₂ (s) + 2 NaNO₃ (aq) How many moles of precipitate will be formed when 242.5 mL of 0.300 M LiI is reacted with excess Pb(NO₃)₂ in the following chemical reaction? 2 LiI(aq) + Pb(NO₃)₂(aq) → PbI₂(s) + 2 LiNO₃(aq) If 19.5 g of NaOH is added to 0.700 L of 1.00 M Co(NO₃)₂, how many grams of Co(OH)₂ will be formed in the following precipitation reaction? 2 NaOH(aq) + Co(NO₃)₂(aq) → Co(OH)₂ (s) + 2 NaNO₃(aq) What mass of aluminum (in g) would be required to completely react with 1.25 L of 0.350 M HCl in the following chemical reaction? 2 Al(s) + 6 HCl(aq) → 2 AlCl₃ (aq) + 3 H₂(g)

Q: A student pipets 17 mL of a lithium sulfate solution into a 274 mL volumetric flask and dilutes to…

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A: Molarity of NaOH = 0.04202 M  Volume of NaOH =32.14 mL Millimoles of NaOH= (0.04202  x 32.14) mmol…

Q: . What mass of precipitate (in g) is formed when 55.2 mL of 0.500 M AlBr₃ reacts with excess AgNO₃…

A: As per our guidelines we can only solve first question. Please resubmit other questions as next…

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A: In this question, we have to find out the correct answer of given problem by the help of the…

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A: The given reaction is: The molarity of HI can be calculated as follows: where MHI is the molarity…

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A: Given reaction is, 2NaI(aq) + Pb(NO₃)₂(aq) → PbI₂(s) + 2NaNO₃(aq) From the given reaction, we can…

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Q: How many moles of precipitate will be formed when 70.0 mL of 2.00 M NaBr is reacted with 300.0 mL of…

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A: Given datas ; Pb(NO3)2 (aq) + 2 NH4I (aq) ---> PbI2 (s) + 2 NH4NO3 (aq)  Moalrity (Conc.) of NH4I…

Q: How many moles of precipitate will be formed

A: Molarity = number of moles/volume of solution (in L)  Number of moles = molarity × volume (in L)

Q: How many moles of precipitate will be formed when 81.2 mL of 0.300 M AgNO₃ is reacted with excess…

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A: Given the volume of 0.320 M Pb(NO3)2(aq) taken = 447 mL * (1L/1000 mL) = 0.447 L => moles of…

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Q: If 27.70 mL of 0.138 M barium hydroxide is required to neutralize 23.0 mL of nitrous acid, what is…

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Q: What volume (in mL) of 0.200 M HCl would be required to completely react with 5.00 g of Al in the…

A: The balanced reaction taking place is given as, => 2 Al (s) + 6 HCl (aq) -----> 2 AlCl3 (aq) +…

Q: What volume (in mL) of 0.250 M HCI would be required to completely react with 4.00 g of Al in the…

A: The given equation is  2 Al(s) + 6 HCl (aq) →2 AlCl3 (aq) +3 H2(g) Concentration HCl=0.250M Mass of…

Q: What quantity in moles of precipitate will be formed when 100.0 mL of 2.00 M NaI is reacted with…

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Q: A 20.0 mL sample of a calcium hydroxide solution, Ca(OH)2 of density 1.10 g/mL, is analyzed by…

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Q: How many moles of precipitate will be formed when 100 mL of 2.00 M NaBr is reacted with 70.0 mL of…

A: The mole of precipitate will be formed has to be determined

Q: How many moles of precipitate will be formed when 108.5 mL of 0.200 M NaBr is reacted with excess…

A: Given,Volume of NaBr = 108.5 mL = 0.1085 L       (1 mL =0.001 L)Molarity of NaBr = 0.200 M = 0.2…

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Q: 20.00-mL portion of the diluted acid is titrated with 0.2025 MNaOH solution. If 42.00 mL of the NaOH…

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Q: Question attached

A: We have Number of moles =Given mass Molar massMass =Number of moles × Molar mass The reactant that…

Q: What mass of precipitate (in g) is formed when 20.5mL of 0.300M Ni(NO3)2 reacts with 24.5mL of…

A: Molarity = moles of solute/volume of solution (L)  So, moles = molarity × volume  Number of moles =…

Q: What quantity in moles of precipitate will be formed when 100.0 mL of 2.00 M NaI is reacted with…

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Q: Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to…

A: (a) No. Of mole of Pb(NO3)2 = (889 x 10-3) L (0.460) M = 0.4089mol 1 mole of Pb(NO3)2 = react with 2…

Q: react

A: Acid: V =15 ml, M =? Base: V = 55.7 ml and M = 0.1 M

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Q: What quantity in moles of precipitate will be formed when 219.5 mL of 0.350 M NaCl is reacted with…

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Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.400 M Mn(NO3)2 reacts with 34.0 mL of…

A: • Given,            [Mn(NO3)2] =0.400 m = 0.4 mole/L            Vmn(NO3)2 =20.5 ml =…

Q: Calculate the number of milliliters of 0.754 M KOH required to precipitate all of the Zn2+ ions in…

A: calculate number of moles of Zn(NO3)2 1 mole of Zn(NO3)2 react with 2moles of KOH to form 1 mole…

Q: What is the molarity of a hydrchloric acid, HCl, solution if it takes 26.90 mL of acid to neutralize…

A: Given Mass of Fe(OH)3 = 7.77 g Volume of HCl solution = 26.90 ml = 0.0269 L

Q: How many moles of precipitate will be formed when 50.0 mL of 0.300 M AgNO₃ is reacted with excess…

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Q: A student pipets 18 mL of a lithium sulfate solution into a 164 mL volumetric flask and dilutes to…

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Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.500 M Cu(NO₃)₂ reacts with 29.0 mL of…

A: [Cu(NO₃)₂] = 0.50 M VCu(NO₃)₂ = 20.5 ml  nCu(NO₃)₂ =  0.50 M x 20.5 ml = 10.25 m mol [NaOH ] = 0.50…

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A: Given 1) mass of Ba(OH)2 = 2.64 g Volume of Ba(OH)2 = 58.7 ml 3) Volume of Ba(OH)2 = 17.4 ml Volume…

Precipitation Titration

Precipitation analysis is used to analyze drugs, and to measure the salt content in food and beverages. It is an important concept from the examination point of view many practical questions are asked on the topic. This topic is significant in the professional exams for both undergraduate and graduate courses, especially for