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Hydrogen peroxide decomposes spontaneously to yield water and oxygen gas according to the reaction equation 2H,0,(aq) → 2H,0(1) + 0,(g) The activation energy for this reaction is 75 kJ-mol¬. The enzyme catalase, found in blood, lowers the activation energy to 8.0 kJ-mol-. At what temperature would the non-catalyzed reaction need to be run to have a rate equal to that of the enzyme-catalyzed reaction at 25 °C?

Hydrogen peroxide decomposes spontaneously to yield water and oxygen gas according to the reaction equation 2H,0,(aq) → 2H,0(1) + 0,(g) The activation energy for this reaction is 75 kJ-mol¬. The enzyme catalase, found in blood, lowers the activation energy to 8.0 kJ-mol-. At what temperature would the non-catalyzed reaction need to be run to have a rate equal to that of the enzyme-catalyzed reaction at 25 °C?

Chemistry by OpenStax (2015-05-04)
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter12: Kinetics
Section: Chapter Questions
Problem 63E: Hydrogen iodide, HI, decomposes in the gas phase to produce hydrogen, H2, and iodine, I2. The value...
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Hydrogen peroxide decomposes spontaneously to yield water and oxygen gas according to the reaction equation 2H,0, аq) — 2H,00) + 0,(9) The activation energy for this reaction is 75 kJ•mol-. The enzyme catalase, found in blood, lowers the activation energy to 8.0 kJ-mol-I At what temperature would the non-catalyzed reaction need to be run to have a rate equal to that of the enzyme-catalyzed reaction at 25 °C? T = K
Transcribed Image Text:Hydrogen peroxide decomposes spontaneously to yield water and oxygen gas according to the reaction equation 2H,0, аq) — 2H,00) + 0,(9) The activation energy for this reaction is 75 kJ•mol-. The enzyme catalase, found in blood, lowers the activation energy to 8.0 kJ-mol-I At what temperature would the non-catalyzed reaction need to be run to have a rate equal to that of the enzyme-catalyzed reaction at 25 °C? T = K
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