mass of 0.400 kg is attached to a spring and set into oscillation on a horizontal frictionless surface. The simple harmonic motion of the mass is described by x(t) = (0.700 m)cos[(20.0 rad/s)t]. Determine the following.    (a) amplitude of oscillation for the oscillating mass  ______ m    (b) force constant for the spring  ______ N/m    (c) position of the mass after it has been oscillating for one half a period  ______ m    (d) position of the mass one-third of a period after it has been released  ______ m

Principles of Physics: A Calculus-Based Text
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Author:Raymond A. Serway, John W. Jewett
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Chapter12: Oscillatory Motion
Section: Chapter Questions
Problem 18P
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A mass of 0.400 kg is attached to a spring and set into oscillation on a horizontal frictionless surface. The simple harmonic motion of the mass is described by x(t) = (0.700 m)cos[(20.0 rad/s)t]. Determine the following.
 
 (a) amplitude of oscillation for the oscillating mass
 ______ m
 
 (b) force constant for the spring
 ______ N/m
 
 (c) position of the mass after it has been oscillating for one half a period
 ______ m
 
 (d) position of the mass one-third of a period after it has been released
 ______ m
 
 (e) time it takes the mass to get to the position x = −0.100 m after it has been released
 ______ s

A mass of 0.400 kg is attached to a spring and set into oscillation on a horizontal frictionless surface. The simple harmonic motion of the mass is described by
x(t) = (0.700 m) cos[(20.0 rad/s)t]. Determine the following.
(a) amplitude of oscillation for the oscillating mass
m
(b) force constant for the spring
N/m
(c) position of the mass after it has been oscillating for one half a period
m
(d) position of the mass one-third of a period after it has been released
m
(e) time it takes the mass to get to the position x = -0.100 m after it has been released
Transcribed Image Text:A mass of 0.400 kg is attached to a spring and set into oscillation on a horizontal frictionless surface. The simple harmonic motion of the mass is described by x(t) = (0.700 m) cos[(20.0 rad/s)t]. Determine the following. (a) amplitude of oscillation for the oscillating mass m (b) force constant for the spring N/m (c) position of the mass after it has been oscillating for one half a period m (d) position of the mass one-third of a period after it has been released m (e) time it takes the mass to get to the position x = -0.100 m after it has been released
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I am confused with part (e).  I don't understand the steps. How is 1.427 obtained?   How is the 20t  moved to the left side of the equation, since it is inside the COS() function?   I am just not understanding the math.   Can you step it through with an explanation at each individual step?

e)
x = 0.7 COS(20.t)
0.1 = 0.7 cos (20+)
20t=1.427 Rad.
+= 0·07 sec
Transcribed Image Text:e) x = 0.7 COS(20.t) 0.1 = 0.7 cos (20+) 20t=1.427 Rad. += 0·07 sec
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