Answered: If the vibrational frequency of 1802 is…

If the vibrational frequency of 1802 is 1764 cm-1, what is the spring constant a.1560 N/m b.1620 N/m c.1640 N/m d.1660 N/m C. X10 K =5.242 x10 f = 5.292x 10

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter27: Molecular Fluorescence Spectroscopy

Section: Chapter Questions

Problem 27.6QAP

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Question

6. If the vibrational frequency of 1802 is 1764 cm-1, what is the spring constant
a.1560 N/m
b.1620 N/m
X10
K = (5.242 x10) (4a2
c.1640 N/m
d.1660 N/m
f = 5.292x 10

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