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PhysicsQ&A LibraryIf two resistors with resistances R1 and R2 are connected in parallel, then the total resistance, R, measured in ohms (Omega sign) is given by:(1/R)=(1/R1)+(1/R2). If R1 is increasing at a rate of .2 ohms/s and R2 is increasing at a rate of .3 ohms/s, how fast is R changing when R1= 80 ohms and R2= 100 ohms.Question

Asked Feb 28, 2020

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If two resistors with resistances R_{1} and R_{2} are connected in parallel, then the total resistance, R, measured in ohms (Omega sign) is given by:

(1/R)=(1/R_{1})+(1/R_{2}). If R_{1} is increasing at a rate of .2 ohms/s and R_{2} is increasing at a rate of .3 ohms/s, how fast is R changing when R_{1}= 80 ohms and R_{2}= 100 ohms.

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