Question 6 5. For each of the following pedigrees, indicate whether the pattern of inheritance is recessive or dominant.4II4 5731345 67 89.10 11III91IV1246. For the right pedigree:What is the genotype of individuals Il-3 and II-4 (hint, look at their children).What is the genotype of individuals IV-5?What is the chance that II-8 is a a carrier?What is the chance for a child of II-8 and IV-5 to have the disease?3.3,2.3.2.

# Here by I am giving solution of only first question. Please send next question again. Pedigree :…

Answered: II 2. 3. 3 5 6 7 10 11 III 2 3 6 7 8 1…

Science

Biology

II 2. 3. 3 5 6 7 10 11 III 2 3 6 7 8 1 2 3 4 8. 4, 8.

Biology: The Dynamic Science (MindTap Course List)

4th Edition

ISBN:9781305389892

Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Chapter13: Genes, Chromosomes, And Human Genetics

Section: Chapter Questions

Problem 2TYK: The following pedigree shows the pattern of inheritance of red green color blindness in a family....

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Individuals affected by a condition known as polydactyly have extra fingers or toes. The following pedigree shows the pattern of inheritance of this trait in one family: From the pedigree, can you tell if polydactyly comes from a dominant or recessive allele? Is the trait sex-linked? As far as you can determine, what is the genotype of each person in the pedigree with respect to the trait?
In cats, the genotype AA produces tabby fur color; Aa is also a tabby, and aa is black. Another gene at a different locus is epistatic to the gene for fur color. When present in its dominant W form (WW or Ww), this gene blocks the formation of fur color and all the offspring are white; ww individuals develop normal fur color. What fur colors, and in what proportions, would you expect from the cross AaWw Aa Ww?
1. Construct a pedigree chart of the trait traced in the situation below.2. The pedigree chart must be constructed with the names and genotypes at the bottom of every individual in the chart.If it is autosomal: Always use the first letter of the dominant trait to represent the dominant allele. For example, if the dominant trait is red, so the allele R-red, while r-yellow. For example, if the person is homozygous dominant for curly hair, we write CC as his genotype. If sex-linked, do not forget to write the parents’ chromosomes (XX-female, XY-male), with their corresponding superscripts (dominant or recessive). The superscript must be based on the first letter of the disorder. For example, the mother is a carrier of hemophilia (which is x-linked recessive), so we write XHXh. If the father has hemophilia, we write XhY. Put the pedigree chart using code properly. The situation is given below: Trait: NeurofibromatosisThe dominant form is neurofibromatosis, caused by the production of…
1. Construct a pedigree chart of the trait traced in the situation below.2. The pedigree chart must be constructed with the names and genotypes at the bottom of every individual in the chart.If it is autosomal: Always use the first letter of the dominant trait to represent the dominant allele. For example, if the dominant trait is red, so the allele R-red, while r-yellow. For example, if the person is homozygous dominant for curly hair, we write CC as his genotype. If sex-linked, do not forget to write the parents’ chromosomes (XX-female, XY-male), with their corresponding superscripts (dominant or recessive). The superscript must be based on the first letter of the disorder. For example, the mother is a carrier of hemophilia (which is x-linked recessive), so we write XHXh. If the father has hemophilia, we write XhY. Put the pedigree chart using code properly. The situation is given below: Trait: NeurofibromatosisThe dominant form is neurofibromatosis, caused by the production of…
7. In rabbits, a locus involved in the control of coat colour may be occupied by any of fouralleles: Full colour (C), Sepia (ck), Cream (cd), or Albino (ca). A geneticist counted the numberof Full colour (C), Sepia (ck), Cream (cd) and Albino coat offspring resulting after crossesbetween Sepia (ck) and Cream (cd) coloured coated parents. The results were as follows.• Full colour (C): 152• Sepia (ck): 53• Cream (cd): 39• Albino (ca): 6Mendelian inheritance of this trait predicts that the ratio of Full colour (C) to Sepia (ck) to Cream(cd) to Albino (ca) should be 9:3:3:1. Do the experimental results support this mode ofinheritance?
12. A heterozygous agouti mink is bred with a true-breeding white mink. Of the three offspring, one is an agouti male, one is a white male, and one is a black female. What is thesimplest explanation as to coat colour inheritance in these mink? the agouti allele is sex-linked a single gene is involved with the agouti allele being dominant a single gene is involved with the white allele being recessive at least two genes are involved
1. The pedigree shown below illustrates the inheritance pattern for a trait controlled by a single fully penetrant gene with complete dominance. Based on the pedigree do the following: a. List one mode of inheritance consistent with the pedigree.
1) By convention, the recessive trait will determine the abbreviation used to track crosses if it is a mutant condition, since it stands out in contrast to the rest of the population. For example, if pea pods are typically green in color, a mutant condition might result in yellow pea pods; therefore, the lowercase letter ‘y’ would be used to depict the mutant state, yellow, while uppercase ‘Y’ would depict the wildtype (wt) condition, green. Remember that the mutant condition is not necessarily always recessive. 1 A) . If green is dominant wt (Y) and yellow is a recessive mutant condition (y), depict a Yy father mated with a YY mother in the Punnett. 1B) Considering the dominant allele, what colors are the parents in the cross above? Yy = _____________________ YY = _____________________ 1C) What colors are the offspring in the cross above? 1D) What is the phenotypic ratio of the offspring? 1E) What is the genotypic ratio of the offspring? (Remember, the genotypic ratio is based…
4.) A man and a woman have a child. The father is blood type A, and one of his parents was blood type A and the other was blood type O. The mother is blood type B, and one of her parents was blood type B, the other type O. Both the father and the mother are carriers of the Bombay allele. (Neither of the type-O grandparents were type O because of the Bombay allele – they had the regular type O genotype.) WhataretheoddsthattheirbabywillhavebloodtypeO? WhataretheoddsthattheirbabywillhavebloodtypeAB? (Hint – for this question, you should draw out a pedigree and fill in as much as you can for the genotypes of BOTH genes that are involved.)
1. Huntington’s disease is a dominant trait inheritance in humans. What is/are the possible genotype/s of the mother if her husband does not exhibit the disease, but their children unfortunately got the disease? A. hh only B. HH only C. HH or Hh D. Hh only 2. Huntington’s disease is a dominant trait inheritance in humans. What is/are the possible genotype/s of the children if both parents do not exhibit Huntington’s disease? A. Hh only B. hh only C. HH or Hh D. HH only 3. Huntington’s disease is a dominant trait inheritance in humans. What is the probability of having a normal child if the mother does not have the disease while her husband has the disease? A. 0% or 50% B. 100% C. 25% D. 0% or 25% E. 50% 4. Huntington’s disease is a dominant trait inheritance in humans. What is the probability of having a girl child with Huntington’s disease if both mother and father has the heterozygous genotype for the disease? A. 0% B. 50% C. 75%…
11. What evidence do you see in the pedigree illustrated if any, allowing the mode of inheritance for this trait to be deduced as completely vs. incompletely dominant? Do not consider any other information beyond what is shown in the pedigree. Answer in one complete sentence, referring to any individuals in the pedigree who may be informative using generation and individual numbers.
1. A human female "carrier" who is heterozygous for the recessive, sex-linked trait causing red-green color blindness (or alternatively, hemophilia), marries a normal male. What proportion of their male progeny will have red-green color blindness (or alternatively, will be hemophiliac)? * a. 100% b. 75% c. 50% d. 25% e. 0% 2. A human female "carrier" who is heterozygous for the recessive, sex-linked trait red color blindness, marries a normal male.What proportion of their female progeny will show the trait? * a. All b. ½ c. ¼ d. 0 e. 3/4 3. Women have sex chromosomes of XX, and men have sex chromosomes of XY. Which of a man's grandparents could not be the source of any of the genes on his Y-chromosome? * a. Father's Mother b. Mother's Father c. Father's Father d. Mother's Mother, Mother's Father, and Father's Mother e. Mother's Mother 4. Male-pattern baldness is an example of a sex-influenced trait. The baldness allele, which causes hair loss, is influenced by the hormones…