Implement the following pseudocode in assembly language. Use short-circuit evaluationand assume that val1 and X are 32-bit variables.if( val1 > ecx ) AND ( ecx > edx )X = 1elseX = 2;

Implement the following expression in assembly language:                                                 EDX = (val3 + val4) - (val2 - val1) - (5/3)*7 Assume that val1, val2, val3 and val4 are 16-bit integer variables You need to implement the expression the way it is provided, you cannot do any reduction on the expression while implementing it. Initialize val1 with 120 (hexadecimal), val2 with 39 (hexadecimal), val3 with 20 (hexadecimal) and val4 with 27 (hexadecimal) You are NOT allowed to update the values of any variables. Use ONLY mov, add, sub, movzx, movsx, or neg instructions whenever needed. Use the debugger to verify your answer.

Given the following code segment in C++, please write its corresponding 68K assembly code. int sum = 0; int c =1; for (unsigned short i = 0; i <= 10; i++) {        if (c == 1 ) {                      sum += i;                      c = 0;        }        else {                      c = 1;        } }

Convert this following C++ code below to easy68k assembly language: int sum = 0; int c =1; for (unsigned short i = 0; i <= 10; i++) { if (c == 1 ) { sum += i; c = 0; } else { c = 1; } }

computer fundamental-hack assembly language

In this implementation, each instruction is provided with its own data independently of how other instructions acquire theirs. We insert a(n): A Multiple Input/Output B The Case of Many Pieces of Information or Directions C Unique Information Only One D Several Insts From One

Implement the following expression in assembly language: result = (val3 + val4) - (val1 – val2) – (30*4)/55- Assume that result,val1, val2, val3 and val4 are 16-bit integer variables- You need to implement the expression the way it is provided, you cannot do any reduction on theexpression while implementing it.- Initialize val1 with 134 (hexadecimal), val2 with 139 (hexadecimal), val3 with 67(hexadecimal) and val4 with 47 (hexadecimal)- You are NOT allowed to update the values of any variables.- Use ONLY mov, add, sub, movzx, movsx, or neg instructions whenever needed.- Use the debugger to verify your answer

Implement the following expression in assembly language: result = (val3 + val4) (vall - val2) (30*4)/55 Assume that result, vall, val2, val3 and val4 are 16-bit integer variables You need to implement the expression the way it is provided, you cannot do any reduction on the expression while implementing it. - Initialize vall with 134 (hexadecimal), va12 with 139 (hexadecimal), val3 with 67 (hexadecimal) and val4 with 47 (hexadecimal) -

Write an assembly language program which takes two integers, A and B, and computes the following expressions. You must use the same variables for A and B throughout all three expressions. Using GNU Assembler x86 AT&T Syntax. Include a MakeFile and document all code. 1)  A * 5  2)  (A + B) - (A / B)   3)  (A - B) + (A * B)

E In the following code block(Reference:Q11), you will a set of assembly instructions with corresponding line numbers (line numbers are for informational purpose only and they are not part of the source code). 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 mov edx, 5 dec ecx jmp LABEL1 mov eax, 1 LABEL1: mul edx jmp ecx mov edx, 0678h sub edx, eax jmp DWORD PTR [edx] neg ebx add ecx, ebx mov eax, 0 For each of the conditions/scenario listed below, indicate the corresponding line number (that cause or is associated with the condition/scenario). Enter 0 (Zero) if the condition is not caused by the block of code. 1) Memory indirect jump: type your answer... type your answer... type your answer... type your answer... 2) Register indirect jump: 3) Relative short jump: type your answer... 5) Two's complement type your answer... 4) Relative near jump: 6) Unreachable code