In a lab experiment, 3.4g of methyl orange product was produced using the following: 2.25g sulfanilic acid, 1.3g sodium nitrite, 1.5ml N,N-dimethylaniline, 10ml NaOH and 2.5g NaCl.SHOW FULL WORKING AND ANSWER BOTH PARTS OF THE QUESTION: 3. How many moles of product did you make? Show your working.The mass of product wasThe molecular weight of product isg/mol.Therefore the number of moles of product was_mol.Calculate the reaction yield.The stoichiometry between the limiting reagent and the product ismol.Therefore, the theoretical maximum number of moles of the product ismol.The actual number of moles of product was_mol.Therefore, the reaction yield was_% (use 1 d.p.)

Methyl Orange is produced from sulphanilic acid ,sodium nitrite, and N,N-dimethylanilin. We have to…

In a lab experiment, 3.4g of methyl orange product was produced using the following: 2.25g sulfanilic acid, 1.3g sodium nitrite, 1.5ml N,N-dimethylaniline, 10ml NaOH and 2.5g NaCl. SHOW FULL WORKING AND ANSWER BOTH PARTS OF THE QUESTION:

In a lab experiment, 3.4g of methyl orange product was produced using the following: 2.25g sulfanilic acid, 1.3g sodium nitrite, 1.5ml N,N-dimethylaniline, 10ml NaOH and 2.5g NaCl. SHOW FULL WORKING AND ANSWER BOTH PARTS OF THE QUESTION:

Introductory Chemistry: A Foundation

8th Edition

ISBN:9781285199030

Author:Steven S. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Donald J. DeCoste

Chapter9: Chemical Quantities

Section: Chapter Questions

Problem 45QAP: For each of the following unbalanced reactions, suppose exactly 5.00 g of each reactant is taken....

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Question

100%

In a lab experiment, 3.4g of methyl orange product was produced using the following: 2.25g sulfanilic acid, 1.3g sodium nitrite, 1.5ml N,N-dimethylaniline, 10ml NaOH and 2.5g NaCl.

SHOW FULL WORKING AND ANSWER BOTH PARTS OF THE QUESTION:

3. How many moles of product did you make? Show your working.
The mass of product was
The molecular weight of product is
g/mol.
Therefore the number of moles of product was
_mol.
Calculate the reaction yield.
The stoichiometry between the limiting reagent and the product is
mol.
Therefore, the theoretical maximum number of moles of the product is
mol.
The actual number of moles of product was_
mol.
Therefore, the reaction yield was
_% (use 1 d.p.)

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