In this week's lab, we learned about extraction. This week's "paper" lab started by dissolving p- toluic acid, p-tertbutylphenol and acetanilide in tertbutylmethyl ether. Suppose a student accidentally extracted the mixture first with 0.5- M NaOH (instead of 0.5M NaHCO3). When the get to the end of the experiment (which will discuss more next week), they find that Beaker B does not contain any p-tertbutylphenol, in fac there is no compound dissolved in the solution in Beaker B. Where is the p-tertbutylphenol that should be in Beaker B? Explain what happened. (I don't want a "spilled" it on the countertop explanation. I want an explanation explained b the concepts learned in this lab.) H. N. p-toluic acid pka = 4.2 p-tertbutyl phenol pka = 10.2 acetanilide pka = 24

Fundamentals Of Analytical Chemistry
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ISBN:9781285640686
Author:Skoog
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Chapter31: Introduction To Analytical Separations
Section: Chapter Questions
Problem 31.17QAP
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Where is the p-tertbuttlphenol that should be in breaker B explain what happened.
In this week's lab, we learned about extraction.
This week's "paper" lab started by dissolving p-
toluic acid, p-tertbutylphenol and acetanilide in
tertbutylmethyl ether. Suppose a student
accidentally extracted the mixture fırst with 0.5
M NaOH (instead of 0.5M NaHC03). When they
get to the end of the experiment (which will
discuss more next week), they find that Beaker
B does not contain any p-tertbutylphenol, in fact
there is no compound dissolved in the solution
in Beaker B.
Where is the p-tertbutylphenol that should be in
Beaker B? Explain what happened. (I don't
want a "spilled" it on the countertop
explanation. I want an explanation explained by
the concepts learned in this lab.)
p-toluic acid
pka = 4.2
p-tertbutyl phenol
pka = 10.2
acetanilide
pka = 24
Transcribed Image Text:In this week's lab, we learned about extraction. This week's "paper" lab started by dissolving p- toluic acid, p-tertbutylphenol and acetanilide in tertbutylmethyl ether. Suppose a student accidentally extracted the mixture fırst with 0.5 M NaOH (instead of 0.5M NaHC03). When they get to the end of the experiment (which will discuss more next week), they find that Beaker B does not contain any p-tertbutylphenol, in fact there is no compound dissolved in the solution in Beaker B. Where is the p-tertbutylphenol that should be in Beaker B? Explain what happened. (I don't want a "spilled" it on the countertop explanation. I want an explanation explained by the concepts learned in this lab.) p-toluic acid pka = 4.2 p-tertbutyl phenol pka = 10.2 acetanilide pka = 24
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