need assistance with revising with what I have so far with these chemical balance equations: 1. Aluminum reacts with copper (ii) bromide to produce aluminum bromide and copper metal: Al + CuBr2 --> AlBr3 + Cu2 (single displacement) 2. Silver nitrate reacts with copper metal to produce copper (ii) nitrate and silver metal. Ag(NO3) + Cu --> 2Cu(NO3) + Ag (single displacement) 3. Magnesium metal reacts with hydrochloric acid to make hydrogen gas and magnesium chloride. Mg + HCl --> H(g) + MgCl (combustion)

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter18: Electrochemistry
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I need assistance with revising with what I have so far with these chemical balance equations:

1. Aluminum reacts with copper (ii) bromide to produce aluminum bromide and copper metal:

Al + CuBr2 --> AlBr3 + Cu2 (single displacement)

2. Silver nitrate reacts with copper metal to produce copper (ii) nitrate and silver metal.

Ag(NO3) + Cu --> 2Cu(NO3) + Ag (single displacement)

3. Magnesium metal reacts with hydrochloric acid to make hydrogen gas and magnesium chloride.

Mg + HCl --> H(g) + MgCl (combustion)

4. Silver nitrate and sodium chloride produce silver chloride and sodium nitrate.

Ag(NO3) + NaCl --> AgCl + Na(NO3) (?)

5. Calcium metal reacts with water to produce calcium hydroxide and hydrogen gas.

Ca(s) + H2O --> Ca(OH) + 2H(g) (combustion)

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Thank you for your explanation, I'm however confused by the multiplication of each. For example, the first one mentions  x 3 to CuBr2 and x 2 to AlBr3, this process of cancelling out to create even moles is the balancing? I also wanted to know what the proper classification was for those three you answered? I felt like I had the first two wrong, I wasn't sure if they were single or double replacement.

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