In a study by Sallie Mae and Gallup, 323 of the 1404 respondents said that they paid for their education by taking out student loans. Find a 90% confidence interval for the proportion of students who paid for their education by taking out students loans.

Q: Della has over 500 songs on her mobile phone, and she wants to estimate what proportion of the songs…

A: The formula for the confidence interval is , CI=p^± Z*p^1-p^n Where,  p^=the proportion in sample…

Q: 3. You want to find out the percent of people who use an iPhone, so you survey 120 random adults, of…

A: Here we need to construct a 95% confidence interval for the population proportion.

Q: In a study of 200 accidents that required treatment in an emergency room, 80 occurred at work. Find…

A: Obtain the 90% confidence interval for the true proportion of accidents that occurred at work. The…

Q: In a recent Dew Research Poll, 500 U.S. adults were asked about their online versus in-store clothes…

A:

Q: In a survey, a random sample of teenagers were asked whether they have a sibling. The resulting…

A:

Q: Out of 156 Nielsen families surveyed about their viewing habits, 43 felt that television was too…

A: We have given that,  Favorable cases (X) = 43 and sample size (N) = 156  Then,  We will find the 99%…

Q: how many people should you sample? 4 80 125 382 383

A: Given : Margin of error: ME = 0.05

Q: Is the difference between the two indicators significant at the 95% confidence level?

A:

Q: In a study of 120 randomly selected families, 50 said they streamed their television content. Find…

A:

Q: If n = 200 and p^ = 0.64, find the margin of error at a 95% confidence level.

A:

Q: A Gallup Youth Survey in 2001 found that of 501 randomly selected teenagers in the U.S., 271 of them…

A: Given Total number of teenagers selected = 501Number of teenagers said who get along with their…

Q: Gallup is a company that carries out daily opinion polls on a variety of topics. In a recent daily…

A: The confidence interval can be found by using the formula p±zp(1-p)n

Q: a research poll institute asked respondents if they fet vulnerable to identify theft. in the poll,…

A: Given Data: n=1002 x=595 α=0.05   Calculating the sample proportion p⏜=xn=5951002=0.5938 As n is…

Q: In a recent poll, 150 people were asked if they liked dogs, and 55% said they did. Find the margin…

A:

Q: If a student provided 90% confidence intervals in all ten questions, how many points would we expect…

A: In the given analysis, we have 10 questions and their correct answers. 10 sample responses from 10…

Q: In the Framingham Offspring study 3630 subjects were on anti-hypertensive medication out of 4657…

A: Note: Hi, thank you for the question. As per our company guideline we are supposed to answer only…

Q: What happens to the margin of error if you increase the confidence level?

A: We know that, Margin of error=zσn

Q: The following table shows the results of a survey in which 1017 adults from the United States, 1060…

A: (1)

Q: A researcher asks 600 people if they received a flu vaccine, and 65% said they did. What is the 95%…

A: From the provided information Sample size (n) = 600 65% said they received a flu vaccine that is…

Q: A random sample of 600 voters in Centreville indicated that 90 of them believed their congressional…

A: Formula for confidence interval for population proportion : CI =p^ ± E  Where ,  p^ is sample…

Q: In a recent poll, 260 people were asked if they liked dogs, and 67% said they did. Find the margin…

A: Given: p = 67%=0.67 n= 260 The value of z at a 90% confidence level is 1.645, which can be found by…

Q: In a previous election, the confidence interval for the proportion of likely voters who would vote…

A: given;confidence interval for the proportion;(0.4401, 0.5199)i.e. (p^-E, p^+E)where  p^ : point…

Q: If n=200 and ˆpp^ (p-hat) =0.39, find the margin of error at a 99% confidence level

A: Find z-critical value:…

Q: In June 2020, a Gallup Poll asked U.S. adults whether immigration was a good thing or a bad thing…

A: Given X=600 n=1000

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll,…

A:

Q: A regional survey of 561 companies asked the vice president of operations how satisfied he or she was…

A:

Q: If 64% of a sample of 550 people leaving a shopping mall claims to have spent over $25 create and…

A: Given,   Sample size = 550 Sample proportion = 0.64   Critical value: Using z-table, the z-critical…

Q: A poll commissioned by the Center on Addiction and Substance Abuse at Columbia University found that…

A: Given that, X = 1340 N = 2000 98% confidence level

Q: The 2010 General Social Survey reported a sample where about 48% of US residents thought marijuana…

A:

Q: A survey​ asks, "If the husband in a family wants​ children, but the wife decides that she does not…

A: We have to create 99% confidence interval for the population proportion.

Q: A Gallup poll of 1487 adults showed that 43% of the respondents have Facebook pages.  Construct a…

A: Confidence Interval: In statistics, we can say a range of values of the specified population…

Q: A random sample of accountants were asked whether they double-check their calculations on a tax…

A: Here the sample proportion is given by, p^ Therefore α level confidence interval is given by, p^ -…

Q: The table shows the results of a survey in which separate samples of 400 adults each from the East,…

A: Given : n = 400 p̂= 0.26

Q: in a recent survey of 1000 adults ages 18 to 40, 34% said they had no credit cards. find the 95%…

A: The sample size n=1000. The sample proportion is 0.34. The confidence level is 95%. The area between…

Q: In a recent poll, 110 people were asked if they liked dogs, and 40% said they did. Find the margin…

A: For 99% confidence intervalα=1-CI=1-0.99=0.01So, zα2=z0.012=z0.005=2.576

Q: Suppose you want to construct an 80% confidence interval for the proportion of businesses that…

A: Given:Margin of Error (E)=3.5%=0.035   For Confidence level 80%, the significance level (α) is…

Q: In a survey of 1037 US adults ages 65 and over, 643 were concerned about getting the flu. A 99%…

A:

Q: A recent study of 750 internet users in Europe found that 35% of internet users were women. What is…

A: It is given that the study of 750 internet users in Europe found that 35% of internet users were…

Q: (d) Use the combined data of 80 students, construct a 95% confidence interval estimate of the…

A: Given that  Total students=n=40+40=80 Number of pass students=X=28+32=60

Q: At one large college, 660 out of the 1500 students surveyed said they plan to take another science…

A: Given that,   x=660,n=1500 The sample proportion is, Critical values: By using the standard normal…

Q: In a recent poll, 410 people were asked if they liked dogs, and 44% said they did. Find the margin…

A: n = 410 p^=0.44 Confidence interval = 95%

Q: A recent survey of 1,000 people found that 90% of Americans support background checks for purchasing…

A:

Q: In a​ poll, 37​% of the people polled answered yes to the question​ "Are you in favor of the death…

A: Given information- Margin of error, E = 5% = 0.05 Confidence level, c = 96% We have given that 37​%…

Q: If a retailer would like to estimate the proportion of their customers who bought an item after…

A: Solution: 3. From the given information, confidence level is 0.90 and E=0.03.

Q: confidence interval for the true proportion

A: We have to find out the confidence interval for the true proportion.

Q: It was found that in a sample of 90 teenage boys, 70% of them have received speeding tickets. What…

A: Given data ,n=90P=70%=0.7The z-value at 90% confidence is1.645=z∝12=1.645

Q: If n=17, (x-bar)=44, and s=8, find the margin of error at a 95% confidence level

A: The sample mean is 44 and standard deviation is 8.

Q: In a​ poll, 69​% of the people polled answered yes to the question​ "Are you in favor of the death…

A: Given: Margin of errorE=0.02 Proportion of people who polled yes p^=0.69 The z value corresponding…

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll,…

A: Given, The sample proportion is,

2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.