In a study by Sallie Mae and Gallup, 323 of the 569respondents said that they paid for their education by taking out student loans. Find a 95% confidence interval for the proportion of students who paid for their education by taking out student loans.

Q: If a retailer would like to estimate the proportion of their customers who bought an item after…

A: Given data,     P=58%=0.58     E=7%=0.07     z-value at 95% confidence is  zc =1.98     n=?

Q: what would be the 90% confidence interval of the true proportion of young adults who have received…

A: Given that sample size is n = 190 And the sample proportion is 70% = 0.7 At 90% confidence level,…

Q: In response to a recent GSS survey on whether the Government should impose strict laws to prohibit…

A: Solution: Let X be the number of subjects said “yes” and n be the sample number of subjects. From…

Q: In a study of 200 accidents that required treatment in an emergency room, 80 occurred at work. Find…

A: Obtain the 90% confidence interval for the true proportion of accidents that occurred at work. The…

Q: In a recent Dew Research Poll, 500 U.S. adults were asked about their online versus in-store clothes…

A:

Q: In a recent poll, 430 people were asked if they liked dogs, and 41% said they did. Find the margin…

A: It is given that the value of n is 430, p hat is 0.41 and the confidence level is 0.99.

Q: Out of 156 Nielsen families surveyed about their viewing habits, 43 felt that television was too…

A: We have given that,  Favorable cases (X) = 43 and sample size (N) = 156  Then,  We will find the 99%…

Q: 1. In a recent poll 62 out of 149 randomly chosen students at Allen High School say they plan to buy…

A:

Q: In a study of 120 randomly selected families, 50 said they streamed their television content. Find…

A:

Q: In a survey of 1037 US adults ages 65 and over, 643 were concerned about getting the flu. A 99%…

A: Given,n=1037x=643p^=xnp^=6431037=0.6201-p^=1-0.620=0.380α=1-0.99=0.01α2=0.005Z0.005=2.58    (from…

Q: In a recent poll, 560 people were asked if they liked dogs, and 22% said they did. Find the margin…

A: For 95% confidence intervalα=1-CI=1-0.95=0.05So, zα2=z0.052=z0.025=1.96

Q: In a survey of 50,00 people, 80% indicated that they listened to their favorite radio station…

A: Hern= 5000 P^ = 0.80 We have to construct 95% ci for p

Q: Of 380 randomly selected medical students, 21 said that they planned to work in a rural community…

A: Given that, Out Of 380 randomly selected medical students, 21 said that they planned to work in a…

Q: Of 380 randomly selected medical​ students, 21 said that they planned to work in a rural community.…

A: Given that 380 randomly selected medical​ students, 21 said that they planned to work in a rural…

Q: Find a 95% confidence interval for the proportion of renters.

A: It is given that  Favourable cases, X = 360 Sample size, n = 600 Confidence interval = 95%

Q: a research poll institute asked respondents if they fet vulnerable to identify theft. in the poll,…

A: Given Data: n=1002 x=595 α=0.05   Calculating the sample proportion p⏜=xn=5951002=0.5938 As n is…

Q: If a student provided 90% confidence intervals in all ten questions, how many points would we expect…

A: In the given analysis, we have 10 questions and their correct answers. 10 sample responses from 10…

Q: In the Framingham Offspring study 3630 subjects were on anti-hypertensive medication out of 4657…

A: Note: Hi, thank you for the question. As per our company guideline we are supposed to answer only…

Q: In a recent poll, 240 people were asked if they liked dogs, and 32% said they did. Find the margin…

A: Find z-critical value:…

Q: In a recent polI, 200 people were asked if they liked dogs, and 15% said they did. Find the margin…

A: From the provided information, Sample size (n) = 200 15% people said they like dogs that is p̂ =…

Q: 4. A market-research firm asked 300 people about their shampoo-purchasing habits. Fifty-five people…

A:

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the​ poll,…

A: Given , n = 1008 x = 598

Q: The following table shows the results of a survey in which 1017 adults from the United States, 1060…

A: (1)

Q: A random sample of 600 voters in Centreville indicated that 90 of them believed their congressional…

A: Formula for confidence interval for population proportion : CI =p^ ± E  Where ,  p^ is sample…

Q: In a sports poll, 142 of 500 randomly selected Americans indicated that they consider themselves to…

A: Given that, In a sports poll, 142 of 500 randomly selected Americans indicated that they consider…

Q: In general, when you increase the confidence level for a confidence interval using the same sample…

A: As confidence level increases critical value is going to increase .  Here they given sample…

Q: Of 254 randomly selected medical students, 25 said that they planned to work in a rural community.…

A: It is given that, the number of students said that they planned to work in natural community   (x)…

Q: In a sample of 600 Ottawa families, it is found that 360 rent their dwellings while 240 own their…

A: It is given that sample size (n) is 360 and x is 240.

Q: in a random sample of 192 college students, 129 had part-time jobs. Find the margin of error for the…

A:

Q: If 64% of a sample of 550 people leaving a shopping mall claims to have spent over $25 create and…

A: Given,   Sample size = 550 Sample proportion = 0.64   Critical value: Using z-table, the z-critical…

Q: A random survey of 36 airline passengers indicates that twelve have never flown before. Find a 95%…

A: We have given that,  Sample size (n) = 36 and favorable cases         (X) = 12 Then,  We Will find…

Q: In a sample of 900 people, 378 say they snooze the alarm more than once in the morning. Find a 95%…

A: Given,   The sample proportion is,

Q: 1. In a poll of 2,500 likely voters, 966 say that the Philippines spend too little on education.…

A:

Q: A poll commissioned by the Center on Addiction and Substance Abuse at Columbia University found that…

A: Given that, X = 1340 N = 2000 98% confidence level

Q: Exercise 3 An employment counselor found that in a sample of 100 unemployed workers, 65% were not…

A: Given that : 1) sample size = 49  Mean = $ 23.45 S. D = $ 2.80 90% confidence interval.

Q: Would represent a 90% confidence interval for the average highway mileage of all Smart Cars?

A: we need to find the confidence interval of the mean GIVEN mean=47 S.D=5 n=15

Q: A Gallup poll of 1487 adults showed that 43% of the respondents have Facebook pages.  Construct a…

A: Confidence Interval: In statistics, we can say a range of values of the specified population…

Q: A random sample of accountants were asked whether they double-check their calculations on a tax…

A: Here the sample proportion is given by, p^ Therefore α level confidence interval is given by, p^ -…

Q: In a survey of 32 students at a local high school, 17 support changing the schools mascot. Find the…

A:

Q: in a recent survey of 1000 adults ages 18 to 40, 34% said they had no credit cards. find the 95%…

A: The sample size n=1000. The sample proportion is 0.34. The confidence level is 95%. The area between…

Q: A recent study of 750 internet users in Europe found that 35% of internet users were women. What is…

A: It is given that the study of 750 internet users in Europe found that 35% of internet users were…

Q: At one large college, 660 out of the 1500 students surveyed said they plan to take another science…

A: Given that,   x=660,n=1500 The sample proportion is, Critical values: By using the standard normal…

Q: In a poll of 2,300 likely voters, 966 say that the Philippines spend too little on education. Find…

A: We have given that the sample size n = 2300, favourable cases X =966 and sample proportion p =…

Q: When 258 college students are randomly selected and surveyed, it is found that 106 own a car. Find a…

A: The provided information is: It is given that 106 college students (s) own a car among 258 college…

Q: If a retailer would like to estimate the proportion of their customers who bought an item after…

A: Solution: 3. From the given information, confidence level is 0.90 and E=0.03.

Q: confidence interval for the true proportion

A: We have to find out the confidence interval for the true proportion.

Q: A survey found that out of 800 workers, 150 said they were interrupted by frank phone calls. Find…

A: Given,n=800x=150p^=xnp^=150800=0.18751-p^=1-0.1875=0.8125α=1-0.95=0.05α2=0.025Z0.025=1.96

Q: Of 380 randomly selected medical students, 21 said that they planned to work in a rural community.…

A: Here we need to construct a 95% confidence interval for the population proportion. Here the sample…

Q: If n=360 and ˆp(p-hat) =0.69, find the margin of error at a 95% confidence level

A:

2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.