In a W52.0ltext{-g}) aqueous solution of methanol, W(\ce(CH_40},W) the mole fraction of methanol is WO.120.11) What is the mass of each component? Wtext(mass of ) lce(CH_40):) W Mext(g \ce(CH_(4]0) W) mass of water: Wtext{g \ce(HL(2)0} W)
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- Hexanoic acid was added to an immiscible biphasic solvent system, water and CCl4 at 20.0OC and the equilibrium concentrations of hexanoic acid were determined to be 3.66 g/L in H2O and 67.0 g/L in CCl4. Caluclate the distrubution coeffiecent (D2) of hexanoic acid in water with respect to CCl4.A solution is prepared by dissolving 40.00 g of MgCl2 (f.w. = 95.211 g mol–1), a non-volatile solute, in enough water (m.w. = 18.02 g mol–1) to result in exactly 2 L of solution at 25 °C. Assume the density of the solution is that of pure water (dsolution = 1.000 g mL–1). The ebullioscopic constant (Kb) for water is 0.513 °C m–1. The cryoscopic constant (Kf) for water is 1.86 °C m–1. The vapor pressure of pure water is 0.0313 atm. Determine the freezing point of the solution.A solution is prepared by dissolving 40.00 g of MgCl2 (f.w. = 95.211 g mol–1), a non-volatile solute, in enough water (m.w. = 18.02 g mol–1) to result in exactly 2 L of solution at 25 °C. Assume the density of the solution is that of pure water (dsolution = 1.000 g mL–1). The ebullioscopic constant (Kb) for water is 0.513 °C m–1. The cryoscopic constant (Kf) for water is 1.86 °C m–1. The vapor pressure of pure water is 0.0313 atm. Determine the osmotic pressure in atm.
- A water carbonating plant is available for use in the home and operates by providingcarbon dioxide at 5.0 atm. Estimate the molarity of the soda water it produces. Hint:Henry’s Law can also be expressed as PB = mBKB where PB is the partial pressure ofsubstance B, mB is the molality of the solution, and KB would be the Henry’s Lawconstant of B. Using this expression, the Henry’s Law constant for CO2 is 3010kPa*kg/mol. You may assume that the density of water is approximately 1.0 g/mL. A) 0.17 MB) 0.017 MC) 0.067 MD) 0.0017 ME) Cannot be determinedAn excess amount of Ba(NO3)2 was added to 2 liters of water at 25 oC until the solution is saturated. Because Ba(NO3)2 is only slightly soluble in water, the excess Ba(NO3)2 was filtered out to get a solid-free mixture. The proponents of the experiment thought about using the concept of colligative properties, specifically boiling point elevation, to determine Ksp. It was observed in their experiments that the solution boils at 100.15 deg C. Kb of water = 0.51 K-kg/mol. Barium nitrate dissociates using: Solve the ff: a) Amount of Ba(NO3)2 dissolved in grams. MW of Ba(NO3)2 = 261.3 g/molb) Solubility product, Kspc) Vapor pressure of the solution in kPaAn automobile antifreeze mixture is made by mixing equal volumes of ethylene glycol (SG= 1.114; MW = 62.07 g/mole) and water at 20oC. The density of the mixture is 1.070 g/mL. Express the concentration of ethylene glycol as:a) Volume percentb) Mass percentc) Molarityd) Molalitye) Mole fraction
- Chloroform (1)/methyl ethyl ketone (2) form a solution in vapor liquid equilibrium at 330 K 1) The chloroform concentration in the liquid phase is x1 = 0.55. Assuming an ideal gas and an ideal solutionof liquids, what are y1 and P (in kPa), to 3 significant figures? 2) Was the “ideal solution of liquids” an accurate assumption in part (a.)? Clearly state Yes/No and explain 1-2 sentencesQ3 / The solubility of sodium chloride NaCl in water at 290 Kis 35.8 kg / 100 kg of water. Express the solubility as the following: 1. Mass fraction and the mass percent of Naci 2. Mole fraction and mole percent of NaCl 3. kmol of NaCl per 1000 kg of water Note: molecular weight of NaCl = 135.8, and water = 18.016The following evidence was obtained from an experiment to determine the solubility of calcium chloride at room temperature. A sample of saturated calcium chloride solution was evaporated to dryness, and the mass of solid residue was measured.EvidenceVolume of solution (mL) = 15.0Mass of empty beaker (g) = 90.54Mass of beaker and residue (g) = 101.36The solubility of calcium chloride is g/100 mL
- A 100-liter empty jar was spiked with 20 mg of TCE (C2HCl3) under room temperature condition. The jar was then closed tightly. What is the concentration (in atm.) of TCE in the air at 25 C? (TCE: MW: 131.4 g/mol; TCE solubility in water (Cs) = 1100 mg/L; Pv (pure liquid at 25oC) = 10^-1.01 atm. KH = 10^1.03 L atm mol-1; KOW = 102.42). if the jar was half filled with water and half filled with air, what were the concentrations of TCE in both air and water at 25C?What would (triangle) Hrxn be for this new situation with 40 ml of both 1.0 M NaOH and 1.0 M HCl, Ccal=166.8, Tempertre final was 28.9 C, the initial temperature was 22.1 C.A batch of 500 ?? of ??? dissolves in water to form a saturated solution at 350 ? (77 °?) where the solubility is 30% by weight of ??? in water. The solution cools at 293 ? (20 °?) at which the solubility is 25.4% by weight. Determine the number of crystals obtained if 3.5% of the original water evaporates on cooling. Also, determine the capacity of the container in which this solution is cooled if it is 1.20 times the volume of the solution. The density of the solution is ???? ??/??