In an array-based implementation of a List, why does the add operation take O(n) time in the average case? Select one: a. The time it takes to shift entries over to make room in the array depends on the number of entries in the List b. The time to copy the current entries into a newly allocated, larger array depends on the number of entries in the List c. The time to access the position in the array to add the new entry depends on the number of entries in the List d. The time to access the position in the array to add the new entry depends on the capacity of the array

Java Program Your program should use 2D arrays to implement simple matrix operations. Your program should do the following: • Read the number of rows and columns of a matrix M1 from the user. Use an input validation loop to make sure the values are greater than 0. • Read the elements of M1 in row major order • Print M1 to the console; make sure you format as a matirx • Repeat the previous steps for a second matrix M2 • Create a matrix M3 that is the transpose of M1 and print it to the console • Check if M1 and M2 can be added (should have the same dimensions). If possible, add M1 and M2 and print the result to the console. Otherwise print an error message. • Extra credit: Multiply M1 and M2 if possible and print to the console. If the matrices cannot be multiplied, print an error message. Implementation requirements: • Use a helper method for reading a positive integer using an input validation loop. • Use a helper method for printing a matrix. Your helper methods should be private and…

Function PrintArray(integer array(?) dataList) returns nothing   integer i   for i = 0; i < dataList.size; i = i + 1      dataList[i] = Get next input      Put dataList to output      Put "_" to output   // Your solution goes here. Modify as needed   i = 0 Complete the PrintArray function to iterate over each element in dataList. Each iteration should put the element to output. Then, put "_" to output. Ex: If dataList's elements are 2 4 7, then output is: 2_4_7_ Function Main() returns nothing   integer array(3) userNums   integer i    for i = 0; i < userNums.size; i = i + 1      userNums[i] = Get next input    PrintArray(userNums)

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