In Java Determine if the statement has valid syntax or not. If not, fix the syntax error. int q+y=90; int import=50;

C# question

(PLEASE USE BASIC  JAVA NOT COMPLEX I AM A BEGINNER THANKS) Canadian phone number has the following format: +1 (604) 295- 8959 Area Code= Three digits starting with 2-9Prefix= Three digits starting with 2-9Subscriber= Any four digits 0-9Write a java program, using loops, that asks the user to enter a phone number then if correct print theArea Code, Prefix, and Subscriber numbers. If not correct, print what is wrong. Sample run:Enter a number or -99 to quit: +1 (604) 277-9999The number is correct with area code: 604, prefix 277, and subscriber 9999Enter a number or -99 to quit: 1 (104) 277-0123Country code doesn’t start with + and area code doesn’t start with a 2-9 number.

#include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0; void calculatechange(int* change){if(*change>0){if(*change>=50){*change-=50;cent50++;}else if(*change>=20){*change-=20;cent20++;}else if(*change>=10){*change-=10;cent10++;}else if(*change>=05){*change-=05;cent05++;}calculatechange(change);}}void printchange(){if(cent50)printf("\n50cents:%d coins",cent50);if(cent20)printf("\n20cents:%d coins",cent20);if(cent10)printf("\n10cents:%d coins",cent10);if(cent05)printf("\n05cents:%d coins",cent05);cent50=0;cent20=0;cent10=0;cent05=0;}void takechange(int* change){scanf("%d",change);getchar();}int main(){int change=0;int firstinput=0;while(1){if(!firstinput){printf("\nEnter the amount:");firstinput++;}else{printf("\n\nEnter the amount to continue or Enter -1 to…