In need of simple Matlab code using Secant function to find roots for the function f(x) = x^3-2x-2 = 0. Root should be 1.76929.

Develop a Matlab function that finds a root of a function f(x) starting from the given initial estimates (-¹) and (0) with a tolerance in function of at least OK using the secant method. Name the function mySecant using as input the anonymous function f, the initial estimates xm1 and x0, the maximum number of iterations to perform N, and the required tolerance in function epsok. As output, the function shall return four scalar variables: the numerical solution x, its tolerance in function tolFunc, its estimated relative error ere, and the number of iterations performed n. If the requested tolerance in function cannot be reached within N iterations, the function shall execute Matlab's error ("...") function with an appropriate error message. Other than this potential error message, do not print out any results to screen or do any plotting within the function. You must minimize the number of function calls required per iteration, by storing function call results in temporary storage…

Using MATLAB functions poly and polyder, compute the relative condition numbers of the roots 1, 2, ..., 20 of the Wilkinson polynomial 20 w(x) = (x1)(x-2)(x - 20) = x²0 210x¹⁹+... 19 with respect to perturbation of the coefficient of 2x¹⁹, a19, from -210 to -210+2-23 Present your results in a tabular form and write your conclusion on the ill-conditioninig of the Wilkinson polynomial. (Recall: condition number for the jth root is kj |a₁x²=1| \w'(x₂)

Use the Matlab function spline to build the cubic spline S3(x) that satisfies the not-a-knot conditions and interpolates the function f(x)=sin(x) in n = 9 linearly spaced nodes in the interval [0, 1] The maximum absolute interpolation error in 180 linearly spaced points in the interval of interpolation is approximately: 4.6539e14 5.2765e-06 1.0727e-01 1.7423e09 4.3333e - 02