In photoelectron spectroscopy, an electron is ejected from an atom by the collision of a UV photon with the surface of the atom. The equation describing this reaction is similar to the photoelectric effect described by Einstein: hv = ½ mv + Ei, where E; is the ionization energy of the atom. In one experiment on potassium, the kinetic energy of the ejected electron was 5.34 x 10°J when the UV source had a wavelength of 162 nm. Calculate the ionization energy of potassium. %3D -19

Chemistry: Principles and Practice
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
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Chapter7: Electronic Structure
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In photoelectron spectroscopy, an electron is ejected from an atom by the collision of a UV photon with
the surface of the atom. The equation describing this reaction is similar to the photoelectric effect described by
Einstein: hv = ½ mv + Ei, where E; is the ionization energy of the atom. In one experiment on potassium, the
kinetic energy of the ejected electron was 5.34 x 10ºJ when the UV source had a wavelength of 162 nm.
Calculate the ionization energy of potassium.
-19
Transcribed Image Text:In photoelectron spectroscopy, an electron is ejected from an atom by the collision of a UV photon with the surface of the atom. The equation describing this reaction is similar to the photoelectric effect described by Einstein: hv = ½ mv + Ei, where E; is the ionization energy of the atom. In one experiment on potassium, the kinetic energy of the ejected electron was 5.34 x 10ºJ when the UV source had a wavelength of 162 nm. Calculate the ionization energy of potassium. -19
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