In Python: Given 4 floating-point numbers. Use a string formatting expression with conversion specifiers to output their product and their average as integers (rounded), then as floating-point numbers. Output each rounded integer using the following: print('{:.0f}'.format(your_value)) Output each floating-point value with three digits after the decimal point, which can be achieved as follows: print('{:.3f}'.format(your_value))   My original code:  import math num1 = float(input()) num2 = float(input()) num3 = float(input()) num4 = float(input()) num_product_float = num1 * num2 * num3 * num4 num_product = int(num_product_float) num_average_float = (num1 + num2 + num3 + num4) / 4 num_average = int(num_average_float) print('{:.0f} {:.0f}'.format(num_product, num_average)) print('{:.3f} {:.3f}'.format(num_product_float, num_average_float)) Input: 8.3 10.4 5.0 4.8 My output 2071 7 2071.680 7.125 Expected output 2072 7 2071.680 7.125   Here the expected outcome is rounding up for some reason so I edited my code:  num_product_float = num1 * num2 * num3 * num4 num_product = math.ceil(num_product_float) So the first input set (8.3 10.4 5.0 4.8) is now coming out correct, but the second is wrong: Input -2.3 -9.0 -6.5 -5.7 My output 767 -5 766.935 -5.875 Expected output 767 -6 766.935 -5.875   This seems to be rounding down, so I changed my code again:  num_average_float = (num1 + num2 + num3 + num4) / 4 num_average = math.floor(num_average_float) Now I got the first and second input values correct, however the third is STILL coming out wrong: Input: -15.2 10.3 7.8 -9.7 My output 11846 -2 11845.330 -1.700 Expected output 11845 -2 11845.330 -1.700   At this point I am lost, when I did the integer converson using int() I know that the program always drops the digits after the decimal however for some reason the output that is expected seems to be rounding up or down. So even though I adjusted using the math.ceil() and math.floor() code I still cant get the final input set to come out right.

PYTHON The metric system uses as a basic measure the meter and the imperial system has its basic measure as feet and inches. Let’s implement two functions, one to convert feet to meter and another to convert from meter to feet. The conversion formulas are the following:\n", " $$1 meter = 3.2808 feet \\\\\n", " 1 foot = 0.3048 meters $$\n", "\n", "Now implement a program that asks the user what type of conversion he wants to make and asks what value he wants to convert. Process the information and prints the value converted. Test your code with the values:\n", "```\n", "10 meters ==> 32.808 feet\n", "10 feet ==> 3.048 meters\n",

Code should be in Python, please 1. Write a program with a car's miles/gallon and gas dollars/gallon (both floats) as input, and output the gas cost for 10 miles, 50 miles, and 400 miles. Output each floating-point value with two digits after the decimal point, which can be achieved as follows:print('{:.2f}'.format(your_value)) Ex: If the input is: 20.0 3.1599 the output is: 1.58 7.90 63.20 Your program must define and call the following driving_cost() function. Given input parameters driven_miles, miles_per_gallon, and dollars_per_gallon, the function returns the dollar cost to drive those miles. Ex: If the function is called with: 50 20.0 3.1599 the function returns: 7.89975 def driving_cost(driven_miles, miles_per_gallon, dollars_per_gallon) Your program should call the function three times to determine the gas cost for 10 miles, 50 miles, and 400 miles.

Run a python program that will receive a chemical formula as an input and will give its molar mass as an output.you can get a dictionnary of the molar Mass of each component (Hydrogen, Oxygen, .) Inputs: Print(" Enter the Chemical Formula" )  : H2O a. Chemical Formula like H2O and with parantheses Fe(C0)3 and with brackets [ ] Output a. Molar Mass : 18 Please create a program like this. If not familiar with chemistry, please create a similar program.