In the Cytochrome P450-catalyzed mono-oxygenation cycle shown below, which transition results in a low-to-high spinconversion of the heme?BAS = 1/2R-HS = 5/2H₂ONR-HR-HN-HFevF(electrophile)R-OH- H₂OR-HOHIIIR-H+PhIOH*E'(nucleophile)NR-HFelllE(nucleophile)Fell0₂binding stepR-HFeSR-HFellC(reductant)D A to BC to DB to CE' to FD to E

The given reaction is cytochrome P-450 Catalyzed mono oxygenation cycle.

In the Cytochrome P450-catalyzed mono-oxygenation cycle shown below, which transition results in a low-to-high spin conversion of the heme? A B S = 1/2 R-H S = 5/2 H₂O R-H R-H O Fe F (electrophile) R-OH - H₂O H* R-H 0-OH Fell S R-H + PhIO Felll H* E' (nucleophile) R-H N 0-0 Fell le E (nucleophile) Fell R-H -0° 0-0 Fell (reductant) 0₂ binding step R-H 4. Fell S D

In the Cytochrome P450-catalyzed mono-oxygenation cycle shown below, which transition results in a low-to-high spin conversion of the heme? A B S = 1/2 R-H S = 5/2 H₂O R-H R-H O Fe F (electrophile) R-OH - H₂O H* R-H 0-OH Fell S R-H + PhIO Felll H* E' (nucleophile) R-H N 0-0 Fell le E (nucleophile) Fell R-H -0° 0-0 Fell (reductant) 0₂ binding step R-H 4. Fell S D

Principles of Instrumental Analysis

7th Edition

ISBN:9781305577213

Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Chapter14: Applications Of Ultraviolet-visible Molecular Absorption Spectrometry

Section: Chapter Questions

Problem 14.15QAP

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