In the figure below M is the midpoint of АВ and PQ- P M A' Thus, we can conclude that AAPM = A by B

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 20CT: In the figure shown, CD bisects AB at point M so that AM=MB. Is it correct to conclude that CM=MD?
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Please help and explain. I answered this once and got it wrong, so I'm not sure why it's anything different. 

In the figure below M is the midpoint of AB and PQ.
P
B
A'
Thus, we can conclude that AAPM = A
by
Transcribed Image Text:In the figure below M is the midpoint of AB and PQ. P B A' Thus, we can conclude that AAPM = A by
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