Asked Nov 12, 2019

In the following reaction C6H12O6(s) + 6O2(g) ➞ 6CO2(g) + 6 H2O(l) if 28 g of Glucose, C6H12O6, are reacted with 7.50 L of O2 at STP (molar mass of C6H12O6 : 180g/mol)

a. How many g of water are produced? (Molar mass of H2O: 18g/mol)


Expert Answer

Step 1

Number of mol of glucose reacted = given mass / molar mass = 28 g / 180 g/mol = 0.155 mol

Number of ...

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