In the Haber Process, hydrogen (H2) gas reacts with nitrogen (N2) gas to produce ammonia: If 100 mol of H2 are reacted with 40 mol of N2 and 14 mol of ammonia (NH3) are produced, then determine the conversion of the limiting reactant. Enter your answer as a percentage, rounded to one decimal place but without the 3 H2g) + N2lg) - 2 NH3(e) "96" symbol. eg. if you think the fractional conversion was 0.6734, then enter "67.3" as your answer.

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Problem 77AP: For each of the following balanced reactions, calculate how many moles of each product would be...
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In the Haber Process, hydrogen (H2) gas reacts with nitrogen (N2) gas to produce ammonia:
3 H2(g) + N2(g) → 2 NH3(g)
If 100 mol of H, are reacted with 40 mol of N, and 14 mol of ammonia (NH3) are produced, then determine the conversion of the limiting reactant. Enter your answer as a percentage, rounded to one decimal place but without the
"6" symbol. e.g. if you think the fractional conversion was 0.6734, then enter "67.3" as your answer.
Transcribed Image Text:In the Haber Process, hydrogen (H2) gas reacts with nitrogen (N2) gas to produce ammonia: 3 H2(g) + N2(g) → 2 NH3(g) If 100 mol of H, are reacted with 40 mol of N, and 14 mol of ammonia (NH3) are produced, then determine the conversion of the limiting reactant. Enter your answer as a percentage, rounded to one decimal place but without the "6" symbol. e.g. if you think the fractional conversion was 0.6734, then enter "67.3" as your answer.
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