
Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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Question
Complete the program by following the comment in the coda.
C++ language
![D#include <iostream>
#include <string>
using namespace std;
//ADD CODE: Add prototypes for the unmix and decipher functions here
aint main()
string code = "K*@*R*S*\037*D*W*D*Q*B*H*R*D* ";
cout << "Step 0:
<< code << endl;
string unmixed;
unmixed = unmix(code);
cout << "Step 1: " << unmixed << endl;
decipher (unmixed);
cout << "Step 2:
<< unmixed << endl;
return e;
a//Function unmix:
// Returns a new string containing
// only the even characters of string s
astring unmix(string s)
{
string ret;
for (int i = 0; i < s.length(); i++)
{
//ADD CODE: if i is even
{
//COMPLETE LINE: add the character at i onto ret
ret +=
}
return ret;
e//Function decipher:
// Implements a Caesar Cipher decoder
|// every character in s will have 1 added on to its value
avoid decipher(string& s)
{
//ADD CODE: write a for loop to that counts i from e to the length of string s
s[i] = s[i] + 1;](https://content.bartleby.com/qna-images/question/ea26996e-a928-4e4d-b4fd-9751c0983a4f/4c00256c-f501-4940-8c1f-519235ae7790/vpbefy8_thumbnail.jpeg)
Transcribed Image Text:D#include <iostream>
#include <string>
using namespace std;
//ADD CODE: Add prototypes for the unmix and decipher functions here
aint main()
string code = "K*@*R*S*\037*D*W*D*Q*B*H*R*D* ";
cout << "Step 0:
<< code << endl;
string unmixed;
unmixed = unmix(code);
cout << "Step 1: " << unmixed << endl;
decipher (unmixed);
cout << "Step 2:
<< unmixed << endl;
return e;
a//Function unmix:
// Returns a new string containing
// only the even characters of string s
astring unmix(string s)
{
string ret;
for (int i = 0; i < s.length(); i++)
{
//ADD CODE: if i is even
{
//COMPLETE LINE: add the character at i onto ret
ret +=
}
return ret;
e//Function decipher:
// Implements a Caesar Cipher decoder
|// every character in s will have 1 added on to its value
avoid decipher(string& s)
{
//ADD CODE: write a for loop to that counts i from e to the length of string s
s[i] = s[i] + 1;
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