#include struct rec {int a; int b;}; void fun(struct rec*); main() fun: sp->a=5 sp->b=26 main: s.a=10 s.b=52 struct rec s = {1, 1}; fun(&s); s.a *=2; s.b *=2; printf("\nmain: s.a = %d s.b = %d", s.a, s.b); void fun(struct rec *sp) struct rec u = {3, 3}; u.b++; sp -> a += u.b; sp -> b += u.a + 22; printf("\nfun: = sp -> a = %d sp -> b = %d ", sp -> a, sp -> b);

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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can you explain this question , i just want basic experession for understanding

it is c programming data structures

5)
#include <stdio.h>
struct rec {int a; int b;};
void fun(struct rec*);
main()
fun: sp->a=5 sp->b=26
{
main: s.a=10 s.b=52
struct rec s = {1, 1};
fun(&s);
s.a *=2;
s.b *=2;
printf("\nmain: s.a = %d s.b = %d", s.a, s.b);
}
void fun(struct rec *sp)
{
struct rec u = {3, 3};
u.b++;
sp -> a += u.b;
sp -> b += u.a + 22;
printf("\nfun: = sp -> a = %d sp -> b = %d ", sp -> a, sp -> b);
/=
Transcribed Image Text:5) #include <stdio.h> struct rec {int a; int b;}; void fun(struct rec*); main() fun: sp->a=5 sp->b=26 { main: s.a=10 s.b=52 struct rec s = {1, 1}; fun(&s); s.a *=2; s.b *=2; printf("\nmain: s.a = %d s.b = %d", s.a, s.b); } void fun(struct rec *sp) { struct rec u = {3, 3}; u.b++; sp -> a += u.b; sp -> b += u.a + 22; printf("\nfun: = sp -> a = %d sp -> b = %d ", sp -> a, sp -> b); /=
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