
Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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Instructions
The program in the
-
Whether the first number entered by the user is less than or equal to the second number and whether both the numbers are nonnegative.
-
Whether the user entered a valid value for the position of the desired number in the Fibonacci sequence.
Rewrite that program so that it checks for these things.
NOTES:
-
If an invalid number is entered for case 1 above, prompt the user to enter both numbers again.
-
If an invalid number is entered for case 2, prompt the user to enter a value until a valid value is entered.
the code:
#include <iostream>
using namespace std;
int main()
{
//Declare variables
int previous1;
int previous2;
int current;
int counter;
int nthFibonacci;
cout << "Enter the first two Fibonacci numbers: "; //Step 1
cin >> previous1 >> previous2; //Step 2
cout << endl;
//verify the first two values
if(previous1<0 && previous2>0)
cout<<"Enter positive value for the first number\n";
else if (previous1>0 && previous2<0)
cout<<"Enter positive value for the second number\n";
else if (previous1<0 && previous2<0)
cout<<"Enter positive values\n";
else if (previous1>=previous2)
cout<<"The first number should be greater than the second number.\n";
else
{
cout << "The first two Fibonacci numbers are " << previous1 << " and " << previous2 << endl; //Step 3
cout << "Enter the position of the desired Fibonacci number: " ; //Step 4
cin >> nthFibonacci; //Step 5
cout << endl;
//verify the position
if(nthFibonacci<1)
cout<<"Enter a valid position.";
else
{
if (nthFibonacci == 1) //Step 6.a
current = previous1;
else if (nthFibonacci == 2) //Step 6.b
current = previous2;
else //Step 6.c
{
counter = 3;
//Steps 6.c.2 – 6.c.5
while (counter <= nthFibonacci)
{
current = previous2 + previous1;
previous1 = previous2;
previous2 = current;
counter++;
}//end while
}//end else
/* Output the Fibonacci number at nth position */
cout<<current;
}//end else
}
return 0;
}//end main
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