Integer numLengths is read from input. Then, numLengths integers are read from input and inserted at the end of lengthList. If an element is at an even index in lengthList, negate the element. Ex: If the input is: 2 49 33 then the output is: -49 33 Note: Index i is even if i % 2 == 0.
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- import java.util.Scanner;import java.util.ArrayList; public class UserIDSorting {// TODO: Write the partitioning algorithm - pick the middle element as the // pivot, compare the values using two index variables l and h (low and high), // initialized to the left and right sides of the current elements being sorted,// and determine if a swap is necessarypublic static int partition(ArrayList<String> userIDs, int i, int k) {} // TODO: Write the quicksort algorithm that recursively sorts the low and // high partitionspublic static void quicksort(ArrayList<String> userIDs, int i, int k) {} public static void main(String[] args) {Scanner scnr = new Scanner(System.in); ArrayList<String> userIDList = new ArrayList<String>(); String userID; userID = scnr.next();while (!userID.equals("-1")) {userIDList.add(userID);userID = scnr.next();}// Initial call to quicksort quicksort(userIDList, 0, userIDList.size() - 1); for (int i = 0; i < userIDList.size(); ++i)…Q2. Write a java program to perform the following task: a) Create a collection ArrayList<String> for Customer class b) Add 5 elements into ArrayList c) Display the element at index 4 d) Display all the elements in the ArrayList using for-each loop e) Remove the values at index 2 f) Add “cst2” in location 2. g) Check if st2 existing inside the collection.import java.util.ArrayList;import java.util.Arrays; public class PS07A{/*** Write the method named mesh.* * Start with two ArrayLists of String, A and B, each with * its elements in alphabetical order and without any duplicates. * Return a new list containing the first N elements from the two * lists. The result list should be in alphabetical order and without * duplicates. A and B will both have a size which is N or more. * Your solution should make a single pass over A and B, taking * advantage of the fact that they are in alphabetical order, * copying elements directly to the new list.* * Remember, to see if one String is "greater than" or "less than" * another, you need to use the compareTo() method, not the < or > * operators. * * Examples:* mesh(["a","c","z"], ["b","f","z"], 3) returns ["a","b","c"]* mesh(["a","c","z"], ["c","f","z"], 3) returns ["a","c","f"]* mesh(["f","g","z"], ["c","f","g"], 3) returns ["c","f","g"]* * @param a an ArrayList of String in alphabetical…
- import java.util.ArrayList;import java.util.Arrays;public class PS{/*** Write the method named mesh.** Start with two ArrayLists of String, A and B, each with* its elements in alphabetical order and without any duplicates.* Return a new list containing the first N elements from the two* lists. The result list should be in alphabetical order and without* duplicates. A and B will both have a size which is N or more.* Your solution should make a single pass over A and B, taking* advantage of the fact that they are in alphabetical order,* copying elements directly to the new list.** Remember, to see if one String is "greater than" or "less than"* another, you need to use the compareTo() method, not the < or >* operators.** Examples:* mesh(["a","c","z"], ["b","f","z"], 3) returns ["a","b","c"]* mesh(["a","c","z"], ["c","f","z"], 3) returns ["a","c","f"]* mesh(["f","g","z"], ["c","f","g"], 3) returns ["c","f","g"]** @param a an ArrayList of String in alphabetical order.* @param b an…using arrays or Arraylist in Java language Write the method filterBySize().* * Given an ArrayList of String, return a new list where only * strings of the given length are retained.* * Examples:* filterBySize(["a", "bb", "b", "ccc"], 1) returns ["a", "b"]* filterBySize(["a", "bb", "b", "ccc"], 3) returns ["ccc"]* filterBySize(["a", "bb", "b", "ccc"], 4) returns []* * @param list the list of Strings to process.* @param n the size of words to retain.* @return a new list of words with the indicated size retained.Write a Java application CountryList. In the main method, do the following:1. Create an array list of Strings called countries.2. Add "Canada", "India", "Mexico", "Peru" in that order.3. Use the enhanced for loop to print all countries in the array list, one per line.4. Add "Spain" at index 15. Replace the element at index 2 with "Vietnam". You must use the set method.6. Replace the next to the last element with "Brazil". You must use the set method. You willlose one point if you use 3 in the set method. Do this in a manner that would replace thenext to the last element, no matter the size of the array list.7. Remove the object "Canada" Do not remove at an index. Your code should work if"Canada" was at a different location. There is a version of remove method that willremove a specific object.8. Get and print the first element followed by "***"9. Call method toString() on countries to print all elements on one line.10. Use the enhanced for loop to print all countries in the array list,…
- in java language import java.util.ArrayList;import java.util.Arrays; Write the method named mesh.* * Start with two ArrayLists of String, A and B, each with * its elements in alphabetical order and without any duplicates. * Return a new list containing the first N elements from the two * lists. The result list should be in alphabetical order and without * duplicates. A and B will both have a size which is N or more. * Your solution should make a single pass over A and B, taking * advantage of the fact that they are in alphabetical order, * copying elements directly to the new list.* * Remember, to see if one String is "greater than" or "less than" * another, you need to use the compareTo() method, not the < or > * operators. * * Examples:* mesh(["a","c","z"], ["b","f","z"], 3) returns ["a","b","c"]* mesh(["a","c","z"], ["c","f","z"], 3) returns ["a","c","f"]* mesh(["f","g","z"], ["c","f","g"], 3) returns ["c","f","g"]* * @param a an ArrayList of String in alphabetical order.*…Convert this Student Array code into Student Singly LinkedList using java. public class Student {static int index=0; int sid;String name;String date;char attendence;static Student[] stdarry=new Student[10];public void insert(int id, String nm, String dt, char att){stdarry[index]=new Student();stdarry[index].sid=id;stdarry[index].name=nm;stdarry[index].date=dt;stdarry[index].attendence=att;index++; }public int search(int id){int check=0;for(int i=0 ;i<index; i++){if(stdarry[i].sid==id){check=i;break;}}return check;}public void display(){ for(int i=0 ;i<index;i++){System.out.println("ID ="+stdarry[i].sid+"| Name ="+stdarry[i].name+"| Date ="+stdarry[i].date+"| Attendence ="+stdarry[i].attendence); }}public void UpdateAttendence( int id, String dt, char att){for(int i=0; i<index ;i++){if(stdarry[i].sid==id && stdarry[i].date==dt){stdarry[i].attendence=att;break;}}}public void showPresentStudent(String dt, char status) {int count = 0;System.out.println("Present Student…P__Given an empty ArrayList<Integer> numList, what are numList's contents after the following operations: numList.add(12);numList.add(14);numList.add(16);numList.set(1, 13);numList.add(0, 10);.
- Write a remove method that removes all items between a Start Index and an End Index (Inclusive) in Java. This is for a class called RArrayList that functions just like an ArrayList.In this problem you will need to sort the provided ArrayList in ascending order and return the sorted list. import java.util.ArrayList;import java.util.Collections;public class SortArrayListAscending{public static ArrayList solution(ArrayList<Integer> list){return new ArrayList<>();}}Implement two out of three of the basic sorting algorithms - Bubble Sort, Selection Sort, and Insertion Sort - in a generic List. Initial code to be completed: #include <iostream>#include "linkedlist.h" void bubbleSort(List*);void selectionSort(List*);void insertionSort(List*); /** * This activity is focused on using Arrays and Linked Lists as two different * implementations of List. It follows that you are only to use the methods of * List and not of the specific array or linkedlist. */int main(void) { // WARNING! Do not modify main method! // Doing so will nullify your score for this activity. char li; cin >> li; List* list; if (li == 'A') { list = new ArrayList(); } else { list = new LinkedList(); } int length; cin >> length; int input; for (int i = 0; i < length; i++) { cin >> input; list->add(input); } char sym; cin >> sym; int arg1; switch (sym) {…