I've been tasked with implementing a boolean function with variables (A,B,C,D) using a dual-4-to-1 multiplexer. Where A and B are the select bits and C and D drive the function. How would I about solving a question like this if say F(A,B,C,D) = m(2, 5, 8, 10, 15) I understand how to do a question like this in terms of a single 4-1 multiplexer, however the dual 4-1 multiplexer is confusing me.

To implement the boolean function F(A, B, C, D) using dual 4-to-1 multiplexers, you can follow these steps. It's important to note that each dual 4-to-1 multiplexer has two 4-to-1 multiplexers within it.

The function F(A, B, C, D) = m(2, 5, 8, 10, 15) means that F is true when the following minterms are true:

1. Minterm 2 (0010 in binary) implies A' B' C D
2. Minterm 5 (0101 in binary) implies A' B C' D'
3. Minterm 8 (1000 in binary) implies A B' C' D'
4. Minterm 10 (1010 in binary) implies A B' C D
5. Minterm 15 (1111 in binary) implies A B C D