Solve it completely otherwise I will downvote L. How many moles of Fe(OH): [K, - 18 * 10") will dissolve in 1.0 liter of waterbuffered at pH = 10.82?2. Given 100.0 ml. of a buffer that is 0.50 M in HOCI and 0.41 Min NaOCI, what is thepH after 10.0 ml. of1.0M NaOH has been added? (K, for HOC-3.5 x 10)3. A S0.00-ml. sample of a.100 M KOH is titrated with 0.268 M HNO, Calculate the plof the solution after 52.00 ml of HNO; is added.Page I4. How many moles of solid NaF would have to be added to 1.0 Lof 1.95 M HF solutionto achieve a buffer of pH 3.35? Assume there is no volume change. (K, for HF -7.210) 5. The following question refers to the following system: A 1.0-liter solution contains 0.25M HF and 0.43 M NaF (K, for HF is 7.2 x 104).What is the pH of this solution?Page 2

As per bartleyby guidelines i answered only first question so please don't mind and post other…

Answered: L. How many moles of FelOH): [K,-L8 x…

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L. How many moles of FelOH): [K,-L8 x 10" will dissolve in 1.0 liter of water buffered at pi = 10.82?

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter11: Solving Equilibrium Problems For Complex Systems

Section: Chapter Questions

Problem 11.16QAP

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Question

Solve it completely otherwise I will downvote

L. How many moles of Fe(OH): [K, - 18 * 10") will dissolve in 1.0 liter of water
buffered at pH = 10.82?
2. Given 100.0 ml. of a buffer that is 0.50 M in HOCI and 0.41 Min NaOCI, what is the
pH after 10.0 ml. of1.0M NaOH has been added? (K, for HOC-3.5 x 10)
3. A S0.00-ml. sample of a.100 M KOH is titrated with 0.268 M HNO, Calculate the pl
of the solution after 52.00 ml of HNO; is added.
Page I
4. How many moles of solid NaF would have to be added to 1.0 Lof 1.95 M HF solution
to achieve a buffer of pH 3.35? Assume there is no volume change. (K, for HF -7.2
10)

5. The following question refers to the following system: A 1.0-liter solution contains 0.25
M HF and 0.43 M NaF (K, for HF is 7.2 x 104).
What is the pH of this solution?
Page 2

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