Lead (II) iodide dissolves in water according to the equation: PbI2 (s) ⇄ Pb2+ (aq) + 2I- (aq)       Kc = 1.3x10-6 What is the concentration of I- present in a saturated solution (i.e., after equilibrium has been established) a) 1.73x10-2 b) 2.38x10-3 c) 1.38x10-2 d) 6.88x10-3 e) 5.41x10-2

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