Let X equal the number of bits in error in the next four bits transmitted. The possible values for X are (0, 1, 2, 3, 4) Suppose that the probabilities are P(x-0)-0.45 P(x-1)-0.19 P(x -2)-0.14 P(x-3)-0.10 P(x-4)-0.10 Find P(XS2) O 060 O022

A survey was conducted among 68 patients admitted to a hospital cardiac unit during a two-week period. The data of the survey are shown below. Let B= the set of patients with high blood pressure. Let C= the set of patients with high cholesterol levels. Let S = the set of patients who smoke cigarettes. Answer parts (a)-(d) below. n(BNS) = 11 n(B n C) = 11 n(B ncns) = 6 n[(B nC) U (BNS) u (CNS)] = 20 n(B) = 30 n(C) = 28 n(S) = 31 ... (a) Find the number of these patients that had either high blood pressure or high cholesterol levels, but not both. The number of patients that had high blood pressure or high cholesterol levels, but not both, is 41 A

A bag contains (x + 1) yellow balls, x black balls and (x – 1) white balls. Probability of getting a yellow ball is (2/15) more than that of getting a white ball. Find the value of x.

It is equally probable that two signals reach a receiver at any instant of the time T. The receiver will be jammed if the time difference in the reception of the two signals is less than T. Find the probability that the receiver will be jammed.

Evaluate L-1{ -(-e¯™s+4T8+ 2+1

For each day that Sasha travels to work, the probability that she will experience a delay due to traffic is 0.2. Eachday can be considered independent of the other days. In the question,  What is the probability that Sasha’s first delay due to traffic will occur after the fifth day of work travel? Why is it that the answer is 0.32768? How did we get the solution?

I'm have a difficult time understanding how to solve (c). I keep getting the answer wrong. If I unsterstand correctly the probabilty of not being femaleP(A) =1-total #of female/total # of male and female and the probability of not have a degree outside of fieldP(B) is 1-degrees outside of field/ total degrees to solve I did P(A)+P(B)- probability of being female with degree in field. then I tried to solve for probability of being male with a degree in the field and it was still incorrect.