Limestone (CaCO3) reacts with HCl according to the equation CaCO; + 2 HCI CaCl2 + H½0 + CO2 > If 1.00 mole of CO2 has a volume of 22.4 L under the reaction conditions, how many Liters of gas can be formed by the reaction of 2.35 g CaCO3 with 2.35 g of HCl?

Chemistry
9th Edition
ISBN:9781133611097
Author:Steven S. Zumdahl
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Chapter5: Gases
Section: Chapter Questions
Problem 46E
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D
Question 23
Limestone (CaCO3) reacts with HCl according to the equation
CaCO3 + 2 HCI
CaCl2 + H20 + CO2
If 1.00 mole of CO2 has a volume of 22.4 L under the reaction conditions, how many Liters of gas can
be formed by the reaction of 2.35 g CaCO3 with 2.35 g of HCl?
O 0.526 L
O 0.722 L
O 2.95 L
O 1.10 L
Transcribed Image Text:D Question 23 Limestone (CaCO3) reacts with HCl according to the equation CaCO3 + 2 HCI CaCl2 + H20 + CO2 If 1.00 mole of CO2 has a volume of 22.4 L under the reaction conditions, how many Liters of gas can be formed by the reaction of 2.35 g CaCO3 with 2.35 g of HCl? O 0.526 L O 0.722 L O 2.95 L O 1.10 L
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