lodine is prepared both in the laboratory and commercially by adding C12(g)C12(g) to an aqueous solution containing sodium iodide. 2Nal(ag)+Cl2(g)→l2(s)+2NACI(ag)2Nal(ag)+Cl2(g)→12(s)+2NACI(ag) How many grams of sodium iodide, Nal,Nal, must be used to produce 73.7 g73.7 g of iodine, 12?
lodine is prepared both in the laboratory and commercially by adding C12(g)C12(g) to an aqueous solution containing sodium iodide. 2Nal(ag)+Cl2(g)→l2(s)+2NACI(ag)2Nal(ag)+Cl2(g)→12(s)+2NACI(ag) How many grams of sodium iodide, Nal,Nal, must be used to produce 73.7 g73.7 g of iodine, 12?
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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lodine is prepared both in the laboratory and commercially by
adding Cl2(g)Cl2(g) to an aqueous solution containing sodium iodide.
2Nal(ag)+Cl2(g)→12(s)+2N2CI(ag)2Nal(ag)+Cl2(g)→12(s)+2NaCl(ag)
How many grams of sodium iodide, Nal,Nal, must be used to
produce 73.7 g73.7 g of iodine, 12?
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Expert Solution
Step 1
Given
2NaI(aq) + Cl2(g)------> I2(s) + 2NaCl(aq)
Molecular weight of NaI = 149.89g/mol
Molecular weight of NaCl = 58.44g/mol
Molecular weight of I2 = 253.80g/mol
Weight of Iodine required = 73.7g
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