Make up a DNA sequence of at least 18 nucleotides and then (2) show the mRNA sequence that will be made via transcription, (3) show the tRNAs that will base pair and deliver the amino acids, and (4) the amino acid sequence of the resulting protein
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Gene Interactions
When the expression of a single trait is influenced by two or more different non-allelic genes, it is termed as genetic interaction. According to Mendel's law of inheritance, each gene functions in its own way and does not depend on the function of another gene, i.e., a single gene controls each of seven characteristics considered, but the complex contribution of many different genes determine many traits of an organism.
Gene Expression
Gene expression is a process by which the instructions present in deoxyribonucleic acid (DNA) are converted into useful molecules such as proteins, and functional messenger ribonucleic (mRNA) molecules in the case of non-protein-coding genes.
Instructions: Express your own gene! (1) Make up a DNA sequence of at least 18
(3) show the tRNAs that will base pair and deliver the amino acids, and (4) the amino
acid sequence of the resulting protein. You can use the single letter abbreviations for
DNA and RNA nucleotides and the three-letter abbreviations for the amino acids.
Step by step
Solved in 2 steps
- INSTRUCTION: = IF BOTH STATEMENT ARE TRUE = IF FIRST STATEMENT IS TRUE WHILE SECOND STATEMENT IS FALSE = IF FIRST STATEMENT IS FALSE WHILE SECOND STATEMENT IS TRUE = IF BOTH STATEMENTS ARE FALSE STAMENT 1: Heterogenous RNA is a term that refers to mRNA that has not been processed STAMENT 2: If the %A of a bacteria is 20%, the amount of guanine is 30% STAMENT 1: A frameshift mutation involves a change in the reading frame used in the translation of an mRNA STAMENT 2: The genetic code is specific because each codon specifies only for one amino acid STAMENT 1: Binding of RNA primer to the DNA is the first step in the transcription cycle STAMENT 2: Translation refers to the synthesis of proteins using the information contained in mRNAINSTRUCTION: = IF BOTH STATEMENT ARE TRUE = IF FIRST STATEMENT IS TRUE WHILE SECOND STATEMENT IS FALSE = IF FIRST STATEMENT IS FALSE WHILE SECOND STATEMENT IS TRUE = IF BOTH STATEMENTS ARE FALSE STAMENT 1: RNA splicing is the step in post transcriptional processing where intervening sequences are removed STAMENT 2: 5’ to 3’ direction is the direction of growth of the peptide chain ANSWER: STAMENT 1: The enzyme that joins the gaps in newly synthesized DNA is called DNA polymerase STAMENT 2: The name of the compound formed when cytosine is bonded to ribose is cytidine ANSWER: STAMENT 1: Codon is a term that refers to the 3-nucleotide code for amino acids in mRNA STAMENT 2: Transition is a kind of mutation where a purine changes to another purine ANSWER:Instruction - Please answer them correctly - Please answer all of them, they are connected. MUTATION Fill in the correct nucleotide base pairing and amino acid sequence of the mutated DNA a. What is the 3’-5’ DNA sequence? (FORMAT: XXX-XXX-XXX-XXX-XXX) b. What is the mRNA sequence? (FORMAT: XXX-XXX-XXX-XXX-XXX) c. What is the tRNA sequence? (FORMAT: XXX-XXX-XXX-XXX-XXX) d. What is the amino acid sequence? (FORMAT: XXX-XXX-XXX-XXX-XXX) e. What is the most convincing type of mutation had occurred? (Frameshift resulting Missense; Frameshift resulting Nonsense; Substitution – Silent; Substitution – Missense; Substitution – Nonsense)
- INSTRUCTION: = IF BOTH STATEMENT ARE TRUE = IF FIRST STATEMENT IS TRUE WHILE SECOND STATEMENT IS FALSE = IF FIRST STATEMENT IS FALSE WHILE SECOND STATEMENT IS TRUE = IF BOTH STATEMENTS ARE FALSE STAMENT 1: Transfer RNA is the RNA that contains anticodon STAMENT 2: The tail added to an mRNA to protect it from nuclease digestion is polyA tail ANSWER: STAMENT 1: Heterogenous RNA is a term that refers to mRNA that has not been processed STAMENT 2: If the %A of a bacteria is 20%, the amount of guanine is 30% ANSWER: STAMENT 1: A frameshift mutation involves a change in the reading frame used in the translation of an mRNA STAMENT 2: The genetic code is specific because each codon specifies only for one amino acid ANSWER:INSTRUCTION: = IF BOTH STATEMENT ARE TRUE = IF FIRST STATEMENT IS TRUE WHILE SECOND STATEMENT IS FALSE = IF FIRST STATEMENT IS FALSE WHILE SECOND STATEMENT IS TRUE = IF BOTH STATEMENTS ARE FALSE STAMENT 1: If 3’ ATTG 5’ is transcribed, the complementary strands is 5’ UAAC 3’ STAMENT 2: Guanine and Cytosine are purine bases ANSWER: STAMENT 1: The general term for the enzyme that connects nucleotide triphosphates in DNA is DNA transferase STAMENT 2: The enzyme that unwinds the double stranded DNA is topoisomerase ANSWER: STAMENT 1: The name of the compound formed when uracil is bonded to ribose is uradine STAMENT 2: The piece of nucleic acid that is complementary to the DNA template and serves as a starting point of replication is called RNA promoter ANSWER:An adult with a history of tanning has his genome sequenced. The beginning of a protein-coding region of his DNA reads ATGGGGATATGGCAT. If the protein-coding region of a healthy adult reads ATGGGGATATGAGCAT, identify the site and type of mutation.
- Give typing answer with explanation and conclusion Which of the following statements regarding the structure and function of tRNA is true? A-The codon / anticodon pairing is absolutely universal among organism. B-The charging of a tRNA does not require energy. C-There are 64 different tRNAs, one for each possible codon. D-Reading 5' to 3', the first base in the anticodon can participate in non Watson and Crick base pairing E- The 3' end of each tRNA has a unique sequence so a specific amino acid can be attached.30 A DNA sequence encoding a five-amino acid polypeptide is given below. …ACGGCAAGATCCCACCCTAATCAGACCGTACCATTCACCTCCT… …TGCCGTTCTAGGGTGGGATTAGTCTGGCATGGTAAGTGGAGGA… b)Give the sequence and polarity of the mRNA encoding the polypeptide. Please explain step-by-step how exactly you go from the DNA sequence given to the final answer.Need help Below is a strand of mRNA with three codons listed on the strand. Imagine the mRNA strand is in the cytoplasm of a cell and translation is in progress. Draw and label all the necessary main players needed for translation to occur. Included in your drawing should also bee 3 tRNAs , these 3 tRNAs should represent two different forms of tRNA. MRNA 5' ------------AUG------------AGG----------GAG
- Give typing answer with explanation and conclusion to all parts Consider the following DNA mRNA sequence: 5’-ACTGATCCATGCCAGGGGTTTTCAACTAAAATGAAA-3’ a) What is the template sequence this mRNA was transcribed from? Include 5’ and 3’ labels. b) Based on this sequence, what you predict would be the resulting peptide sequence from it. c) In examining this sequence what is the proper reading frame of the open reading frame? (+1, +2, +3, -1, -2, or -3). d) What would you predict the peptide sequence to be if there was the following mutation that led to a base change: 5’-ACTGATGCATGCCAGGGGTTTTCAACTAAAATGAAA-3’INSTRUCTION: = IF BOTH STATEMENT ARE TRUE = IF FIRST STATEMENT IS TRUE WHILE SECOND STATEMENT IS FALSE = IF FIRST STATEMENT IS FALSE WHILE SECOND STATEMENT IS TRUE = IF BOTH STATEMENTS ARE FALSE STAMENT 1: UGA, UAG and UCG are termination codon STAMENT 2: Missense mutation is a type of mutation that changes the coded amino acid ANSWER: STAMENT 1: Binding of RNA primer to the DNA is the first step in the transcription cycle STAMENT 2: Translation refers to the synthesis of proteins using the information contained in mRNA ANSWER: STAMENT 1: The carbon number in ribose where guanine is connected is 1 STAMENT 2: The other name for unprocessed eukaryotic RNA is raw nuclear RNA ANSWER:Transcribe the following DNA sequence. Then translate the resulting mRNA transcript. GGACTACGTTCAAAAGCCATGGATTCGGTA Transcription: Translation: What would be the result of the following mutations in the DNA sequence above? How would the polypeptide change? How would you characterize this mutation? (Nucleotides are numbered from left to right.) a) nucleotide number 16 changes from a G to an A b) nucleotide number 12 changes from an A to a T c) nucleotide number 8 changes from a G to an A d) an insertion of a C between nucleotides 14 and 15.