Me HN Ме. NH NH2 N. N. IC50 31nM IC50 AG > 1.8 kcal mol-1 N. 12nM R R R s-cis s-trans СOMT СOMT H2N H2N Gln120 Gln120 Me NH HNH: N N……HN/ Ser119 ' HN Ser119 N R R No hydrogen-bonds between water molecule and protein

Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter30: Nutrition
Section: Chapter Questions
Problem 30.63P
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The figure below shows two COMT inhibitors (4 and 5). Inhibitor 4 exists in two conformations in bulk solution. The complex formed between COMT and inhibitors 4 and 5 is also shown in the figure. Explain why structure 5 (IC50 12nM) is a more effective inhibitor than structure 4 (IC50 31 nM), and explain why the difference in binding affinity is small.

Me
HN
Me,
HN.
NH2
N.
N.
N.
N°
IC50 12nM
AG > 1.8 kcal mol-1 N
5
IC50 31nM
4
s-cis
s-trans
COMT
COMT
H2N
H2N
Gln120
Gin120
HNH.O
Me
NH.
N
' HN/ Ser119
NHN/ Ser119
R
No hydrogen-bonds between
water molecule and protein
5
Transcribed Image Text:Me HN Me, HN. NH2 N. N. N. N° IC50 12nM AG > 1.8 kcal mol-1 N 5 IC50 31nM 4 s-cis s-trans COMT COMT H2N H2N Gln120 Gin120 HNH.O Me NH. N ' HN/ Ser119 NHN/ Ser119 R No hydrogen-bonds between water molecule and protein 5
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