Methyl salicylate (oil of wintergreen) is prepared by heating salicylic acid, C,HO3, with methanol, CH3 OH. CHsO3 + CH3OH C& Hg O3 + H2O In an experiment, 1.20 g of salicylic acid is reacted with 12.2 g of methanol. The yield of methyl salicylate, CgHg O3, is 1.02 g. What is the percentage yield? Percentage yield = Submit Answer Try Another Version 6 item attempts remaining

General, Organic, and Biological Chemistry
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Chapter6: Chemical Calculations: Formula Masses, Moles, And Chemical Equations
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Problem 6.84EP: In an experiment designed to produce calcium oxide by the chemical reaction 2Ca + O2 2CaO 177.2 g...
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Methyl salicylate (oil of wintergreen) is prepared by heating salicylic acid, C7H&O3, with methanol, CH3 OH.
C, HsO3 + CH3 OH C&Hg O3 + H20
In an experiment, 1.20 g of salicylic acid is reacted with 12.2 g of methanol. The yield of methyl salicylate, Cg Hg O3, is 1.02 g. What is the percentage yield?
Percentage yield = %
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Transcribed Image Text:[References] Methyl salicylate (oil of wintergreen) is prepared by heating salicylic acid, C7H&O3, with methanol, CH3 OH. C, HsO3 + CH3 OH C&Hg O3 + H20 In an experiment, 1.20 g of salicylic acid is reacted with 12.2 g of methanol. The yield of methyl salicylate, Cg Hg O3, is 1.02 g. What is the percentage yield? Percentage yield = % Submit Answer Try Another Version 6 item attempts remaining Visited
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