Morgan observed a higher number of recombinant offspring involvingeye color and wing length (401 + 318) than recombinants forbody color and eye color (17 + 12). These results occurred because a. the genes affecting eye color and wing length are fartherapart on the X chromosome than are the genes affectingbody color and eye color.b. the genes affecting eye color and wing length are closer togetheron the X chromosome than are the genes affectingbody color and eye color.c. the gene affecting wing length is not on the X chromosome.d. the gene affecting body color is not on the X chromosome.

Morgan observed a higher number of recombinant offspring involvingeye color and wing length (401 + 318) than recombinants forbody color and eye color (17 + 12). These results occurred because a. the genes affecting eye color and wing length are fartherapart on the X chromosome than are the genes affectingbody color and eye color.b. the genes affecting eye color and wing length are closer togetheron the X chromosome than are the genes affectingbody color and eye color.c. the gene affecting wing length is not on the X chromosome.d. the gene affecting body color is not on the X chromosome.

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter15: Genomes And Genomics

Section: Chapter Questions

Problem 2QP: Hemophilia and color blindness are both recessive conditions caused by genes on the X chromosome. To...

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Hemophilia and color blindness are both recessive conditions caused by genes on the X chromosome. To calculate the recombination frequency between the two genes, you draw a large number of pedigrees that include grandfathers with both hemophilia and color blindness, their daughters (who presumably have one chromosome with two normal alleles and one chromosome with two mutant alleles), and the daughters sons. Analyzing all the pedigrees together shows that 25 grandsons have both color blindness and hemophilia, 24 have neither of the traits, 1 has color blindness only, and 1 has hemophilia only. How many centimorgans (map units) separate the hemophilia locus from the locus for color blindness?
Human females have two X chromosomes XX; males have one X and one Y chromosome XY. a. With respect to X-linked alleles, how many different types of gametes can a male produce? b. A female homozygous for an X-linked allele can produce how many types of gametes with respect to that allele? c. A female heterozygous for an X-linked allele can produce how many types of gametes with respect to that allele?
In your own words, explain why a testcross cannot produce more than 50% recombinant offspring. When a testcross does produce 50% recombinant offspring, what does this result mean?
The recombinant offspring of the F2 generation were produced bycrossing over that occurreda. during spermatogenesis in the P generation males.b. during oogenesis in the P generation females.c. during spermatogenesis in the F1 males.d. during oogenesis in the F1 females. [Answer the multiple-choice questions based on the following experiment:P generation: True-breeding flies with red eyes and long wings werecrossed to flies with white eyes and miniature wings. All F1 offspringhad red eyes and long wings.The F1 female flies were then crossed to males with white eyes and miniaturewings. The following results were obtained for the F2 generation:129 red eyes, long wings133 white eyes, miniature wings71 red eyes, miniature wings67 white eyes, long wings]
You breed two monster parents (green, hairless) GGhh and ggHH (white, hairy) to produce F1 offspring (green, hairy). Genes G and H are on the same chromosome. a. What are the dominant phenotypes? b. What are ALL of the potential gamete genotypes that could be created by an F1? Clearly indicate the recombinant genotypes. c. Explain how recombinants are created. d. What are the potential offspring genotypes from the cross of a F1 monster with a homozygous recessive monster. e. From this test cross you get 152 green, hairless; 23 green, hairy; 148 white, hairy, and 27 white, hairless. Calculate the chi squared to test the independent assortment hypothesis and determine if these genes assort independently.
A geneticist determines that the order of four genes on a specific chromosome is CABD because the recombination frequencies were 35% for C-D, 24% for A-D, 23% for B-D, and 10% for A-B. What has the geneticist constructed?
In the experiment of Figure shown, Stern followed the inheritancepattern in which females carried two abnormal X chromosomesto correlate genetic recombination with the physical exchange ofchromosome pieces. Is it necessary to use a strain carrying twoabnormal chromosomes, or could he have used a strain in whichfemales carried one normal X chromosome and one abnormal Xchromosome with a deletion at one end and an extra piece of the Ychromosome at the other end?
In the accompanying pedigree, the vertical lines stand for protan color blindness, and the horizontal lines stand for deutan color blindness. These are separate conditions causing different misperceptions of colors; each is determined by a separate gene.a. Does the pedigree show any evidence that the genes are linked? b. If there is linkage, does the pedigree show any evidence of crossing over? Explain your answers to parts a and b with the aid of the diagram. c. Can you calculate a value for the recombination between these genes? Is this recombination by independent assortment or by crossing over?(picture added)
What is the difference between a monohybrid cross and a dihybrid cross? A. A monohybrid cross involves a single parent, whereas a dihybrid cross involves two parents. B. A monohybrid cross produces a single progeny, whereas a dihybrid cross produces two progeny. C. A monohybrid cross involves organisms that are heterozygous for a single trait, whereas a dihybrid cross involves organisms that are heterozygous for two traits. D. A monohybrid cross is performed only once, whereas a dihybrid cross is performed twice.
In a species of firefly, wide wings (W) are dominant to narrow wings (w) and graybodies (C) are dominant to brown bodies (c). A WwCc and wwcc fly were mated andproduced the following offspring: (in the picture attached) What is the recombination frequency for this cross (in percent)?
For a certain gene in a diploid organism, eight units ofprotein product are needed for normal function. Eachwild-type allele produces five units.a. If a mutation creates a null allele, do you think thisallele will be recessive or dominant?b. What assumptions need to be made to answer part a?
Hemophilia and color blindness are both recessive conditions caused by genes on the X chromosome . To calculate the recombination frequency between the two genes, you draw a large number of pedigrees that include grandfathers with both hemophilia and color blindness , their daughters (who presumably have one chromosome with two normal alleles and one chromosome with two mutant alleles), and the daughters’ sons. Analyzing all the pedigrees together shows that 25 grandsons have both color blindness and hemophilia 24 have neither of the traits , 1 has color blindness only and 1 has hemophilia only . how many centimorgans seperate the hemophilia locus from the locus of the color blindness.