BIOLOGY:CONCEPTS+APPL.(LOOSELEAF)
10th Edition
ISBN: 9781305967359
Author: STARR
Publisher: CENGAGE L
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 14, Problem 2GP
Human females have two X chromosomes (XX); males have one X and one Y chromosome (XY).
| a. With respect to X-linked alleles, how many different types of gametes can a male produce? b. A female homozygous for an X-linked allele can produce how many types of gametes with respect to that allele? c. A female heterozygous for an X-linked allele can produce how many types of gametes with respect to that allele? |
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Human females have two X chromosomes (XX); males have one X and one Y chromosome (XY). a. With respect to X chromosome alleles, how many different types of gametes can a male produce? b. If a female is homozygous for an allele on an X chromosome, how many types of gametes can she produce with respect to that allele? c. If a female is heterozygous for an X chromosome allele, how many types of gametes can she produce with respect to that allele?
Given a cross between
AabbCcDdEeFFGgHh x AaBbCcDdEEffggHH,
a) how many possible gametes can the first individual produce?
b) what proportion of the offspring will phenotypically resemble the first parent?
c) what proportion of the offspring will genotypically resemble the second parent?
d) how many phenotypes can be expected from the cross?
A human individual is phenotypically female, but her interphase somatic nuclei show the presence of 2 Barr bodies.
(a) How many X-chromosomes would you expect to see in her karyotype? (b) Explain your answer.
(c) How many chromosomes would you expect to find in this female’s karyotype?
Chapter 14 Solutions
BIOLOGY:CONCEPTS+APPL.(LOOSELEAF)
Ch. 14 - Constructing a family pedigree is particularly...Ch. 14 - Prob. 2SACh. 14 - Prob. 3SACh. 14 - Prob. 4SACh. 14 - Prob. 5SACh. 14 - A trait that is present in a male child but not in...Ch. 14 - Color blindness is a case of ________ inheritance....Ch. 14 - Prob. 8SACh. 14 - Alleles for Tay-Sachs disease are inherited in an...Ch. 14 - Prob. 10SA
Ch. 14 - Prob. 11SACh. 14 - Prob. 12SACh. 14 - Prob. 13SACh. 14 - Klinefelter syndrome XXY can be easily diagnosed...Ch. 14 - Match the chromosome terms appropriately. ___...Ch. 14 - Does the phenotype indicated by the red circles...Ch. 14 - Human females have two X chromosomes XX; males...Ch. 14 - Somatic cells of individuals with Down syndrome...Ch. 14 - An allele responsible for Marfan syndrome Section...Ch. 14 - Both Duchenne muscular dystrophy and color...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Human sex chromosomes are XX for females and XY for males. a. With respect to an X-linked gene, how many different types of gametes can a male produce? b. If a female is homozygous for an X-linked allele, how many different types of gametes can she produce with respect to this allele? c. If a female is heterozygous for an X-linked allele, how many different types of gametes can she produce with respect to this allele?arrow_forwardA certain type of congenital deafness in humans is caused by a rare autosomal (not X-linked) dominant gene. (a) In a mating involving a deaf man and a deaf woman (both heterozygous), would you expect all the children to be deaf? Explain your answer. (b) In a mating involving a deaf man and a deaf women (both heterozygous), could all the children have normal hearing? Explain your answer. (c) Another form of deafness is caused by a rare autosomal recessive gene. In a mating involving a deaf man and a deaf woman, could some of the children have normal hearing? Explain your answer.arrow_forwardLet us suppose that two long-winged flies were crossed and that 77 long-winged and 24 short-winged specimens were counted in the offspring. a. Will the short-winged character be dominant or recessive?B. What will the genotypes of the parents be?C. What is the observed genotype ratio?arrow_forward
- Choose correct option and do explain. Considering an X-linked dominant trait, if an affected woman and an unaffected man decide to have children, which of the answer choices is possible for their children? a. All of their sons are expected to show the dominant trait. b. Their daughters are expected be heterozygous for the gene. c. Their daughters are not expected to show the dominant trait. d. Their sons are expected to be heterozygous for the gene. e. All their children, whether male or female, are expected to show the dominant trait.arrow_forwardYou have a true-breeding strain of miniature-winged fruit flies, where this wing trait is recessive to the normal long wings. How would you show whether the miniature wing trait is sex-linked or autosomal?arrow_forwardIn a cross between a homozygous red-eyed female fruit fly and a white-eyed male fruit fly, what is the expected outcome? a. all white-eyed male offspring b. all white-eyed female offspring c. all red-eyed offspring d. half white-eyed make offspringarrow_forward
- The F1 flies described in question 1 were mated with brown-eyed flies from a true-breeding line. What phenotypes would you expect the offspring to have? (a) all with red eyes (b) all with brown eyes (c) half with red eyes and half with brown eyes (d) red-eyed females and brown-eyed males (e) brown-eyed females and red-eyed malesarrow_forwardHemophilia and color blindness are both recessive conditions caused by genes on the X chromosome. To calculate the recombination frequency between the two genes, you draw a large number of pedigrees that include grandfathers with both hemophilia and color blindness, their daughters (who presumably have one chromosome with two normal alleles and one chromosome with two mutant alleles), and the daughters sons. Analyzing all the pedigrees together shows that 25 grandsons have both color blindness and hemophilia, 24 have neither of the traits, 1 has color blindness only, and 1 has hemophilia only. How many centimorgans (map units) separate the hemophilia locus from the locus for color blindness?arrow_forwardGiven the karyotype shown at right, is this a male or a female? Normal or abnormal? What would the phenotype of this individual be?arrow_forward
- Phenylketonuria (PKU) is a disease that results from a recessive gene.Suppose that two unaffected parents produce a child with PKU. a. What is the probability that a sperm from the father will contain the PKU allele?b. What is the probability that an egg from the mother will contain the PKU allele?c. What is the probability that their next child will have PKU?d. What is the probability that their next child will be heterozygous for the PKU gene?arrow_forwardPhenylketonuria (PKU) is a disease that results from a recessive gene. Suppose that two unaffected parents produce a child with PKU. a. What is the probability that a sperm from the father will contain the PKU allele? b. What is the probability that an egg from the mother will contain the PKU allele? c. What is the probability that their next child will have PKU? d. What is the probability that their next child will be heterozygous for the PKU gene?arrow_forwardScale color in a lizard species is inherited via a single gene with 6 different alleles. (a) How many different types of gametes would be possible in this system? (b) What is the maximum number of different types of scale color gametes that could be produced from one individual lizard?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Human Biology (MindTap Course List)BiologyISBN:9781305112100Author:Cecie Starr, Beverly McMillanPublisher:Cengage Learning
Biology (MindTap Course List)BiologyISBN:9781337392938Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. BergPublisher:Cengage Learning
Human Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage Learning
Concepts of BiologyBiologyISBN:9781938168116Author:Samantha Fowler, Rebecca Roush, James WisePublisher:OpenStax College
Biology: The Dynamic Science (MindTap Course List)BiologyISBN:9781305389892Author:Peter J. Russell, Paul E. Hertz, Beverly McMillanPublisher:Cengage Learning
Human Biology (MindTap Course List)
Biology
ISBN:9781305112100
Author:Cecie Starr, Beverly McMillan
Publisher:Cengage Learning
Biology (MindTap Course List)
Biology
ISBN:9781337392938
Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg
Publisher:Cengage Learning
Human Heredity: Principles and Issues (MindTap Co...
Biology
ISBN:9781305251052
Author:Michael Cummings
Publisher:Cengage Learning
Concepts of Biology
Biology
ISBN:9781938168116
Author:Samantha Fowler, Rebecca Roush, James Wise
Publisher:OpenStax College
Biology: The Dynamic Science (MindTap Course List)
Biology
ISBN:9781305389892
Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan
Publisher:Cengage Learning
Mitochondrial mutations; Author: Useful Genetics;https://www.youtube.com/watch?v=GvgXe-3RJeU;License: CC-BY