N20,(9) = 2 NO2(g) Equilibrium Concentration K = 0.880 NO2 0.149 M N304 0.0253 M 0.5 1.5 2 2.5 3 3.5 Volume Equilibrium Mole Fraction 3.00 L NO, 0.855 Temperature 50 °C N,0, 0.145 Calculate Clear 0.5 1 1.5 2 2.5 3 3.5 Volume (L) Compare the system (still at 50 °C) with a volume of 1.0 L and with 3.0 L. What is the total amount of gas (mol) present in the container at each of these volumes? at 1.0 L X mol at 3.0 L X mol Mole fraction Concentration (M) (n/ntot)

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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N20,(9) = 2 NO2(g)
Equilibrium
Concentration
K = 0.880
NO2 0.149 M
N304 0.0253 M
0.5
1.5
2
2.5
3
3.5
Volume
Equilibrium
Mole Fraction
3.00 L
NO, 0.855
Temperature
50 °C
N,0, 0.145
Calculate
Clear
0.5
1
1.5
2
2.5
3
3.5
Volume (L)
Compare the system (still at 50 °C) with a volume of 1.0 L and with 3.0 L. What is the total amount of gas (mol) present in the container at each of these volumes?
at 1.0 L
X mol
at 3.0 L
X mol
Mole fraction
Concentration (M)
(n/ntot)
Transcribed Image Text:N20,(9) = 2 NO2(g) Equilibrium Concentration K = 0.880 NO2 0.149 M N304 0.0253 M 0.5 1.5 2 2.5 3 3.5 Volume Equilibrium Mole Fraction 3.00 L NO, 0.855 Temperature 50 °C N,0, 0.145 Calculate Clear 0.5 1 1.5 2 2.5 3 3.5 Volume (L) Compare the system (still at 50 °C) with a volume of 1.0 L and with 3.0 L. What is the total amount of gas (mol) present in the container at each of these volumes? at 1.0 L X mol at 3.0 L X mol Mole fraction Concentration (M) (n/ntot)
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