ndirect EDTA determination of cesium. Cesium ion does not form a strong EDTA complex, but it can be analyzed by adding a known volume of NaBil, in cold concentrated acetic acid containing excess Nal. Solid Cs, Bi, I, is precipitated, filtered, and emoved. The excess yellow Bil, is then titrated with EDTA. The end point occurs when the yellow color disappears. (Sodium hiosulfate is used in the reaction to prevent the liberated I from being oxidized to yellow aqueous I, by O, from the air.) The orecipitation is fairly selective for Cst. The ions Lit, Na*, K*, and low concentrations of Rbt do not interfere, although TIt loes. Suppose that 23.00 mL of an unknown containing Cs+ were treated with 23.00 mL of 0.07719 M NaBil, and the inreacted Bil, required 18.74 mL of 0.0552 M EDTA for a complete titration. Find the concentration of Cs+ in the unknown. [Cs*] =

Fundamentals Of Analytical Chemistry
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Chapter31: Introduction To Analytical Separations
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Problem 31.18QAP
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Indirect EDTA determination of cesium. Cesium ion does not form a strong EDTA complex, but it can be analyzed by adding a
known volume of NaBil, in cold concentrated acetic acid containing excess Nal. Solid Cs, Bi, I, is precipitated, filtered, and
removed. The excess yellow Bil, is then titrated with EDTA. The end point occurs when the yellow color disappears. (Sodium
thiosulfate is used in the reaction to prevent the liberated I- from being oxidized to yellow aqueous I, by O, from the air.) The
precipitation is fairly selective for Cst. The ions Lit, Na*, K*, and low concentrations of Rbt do not interfere, although TI
does. Suppose that 23.00 mL of an unknown containing Cs were treated with 23.00 mL of 0.07719 M NaBil, and the
unreacted Bil, required 18.74 mL of 0.0552 M EDTA for a complete titration. Find the concentration of Cs+ in the unknown.
[Cs*] =
M
Transcribed Image Text:Indirect EDTA determination of cesium. Cesium ion does not form a strong EDTA complex, but it can be analyzed by adding a known volume of NaBil, in cold concentrated acetic acid containing excess Nal. Solid Cs, Bi, I, is precipitated, filtered, and removed. The excess yellow Bil, is then titrated with EDTA. The end point occurs when the yellow color disappears. (Sodium thiosulfate is used in the reaction to prevent the liberated I- from being oxidized to yellow aqueous I, by O, from the air.) The precipitation is fairly selective for Cst. The ions Lit, Na*, K*, and low concentrations of Rbt do not interfere, although TI does. Suppose that 23.00 mL of an unknown containing Cs were treated with 23.00 mL of 0.07719 M NaBil, and the unreacted Bil, required 18.74 mL of 0.0552 M EDTA for a complete titration. Find the concentration of Cs+ in the unknown. [Cs*] = M
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