Chromium (III) ion was complexed with EDTA and determined via back-titration. Given the following data, compute for %CrCl3 (MM=158.35) in a 2.63 g sample. Conc. of EDTA titrant: 0.0103 M Volume used: 5.00 mL Conc. of Zn2+ back titrant: 0.0112 M Volume used: 1.32 mL

Chromium (III) ion was complexed with EDTA and determined via back-titration. Given the following data, compute for %CrCl3 (MM=158.35) in a 2.63 g sample. Conc. of EDTA titrant: 0.0103 M Volume used: 5.00 mL Conc. of Zn2+ back titrant: 0.0112 M Volume used: 1.32 mL

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter26: Molecular Absorption Spectrometry

Section: Chapter Questions

Problem 26.14QAP

See similar textbooks

Related questions

Q: 13. A sample contained Cr(III) species. A 25.00 mL portion of this sample is combined with 10.00 mL…

A: Given data : Volume of Cr(III) sample = 25.0 mL = 25×10-3 L Concentration of CDTA = 0.0875 M Volume…

Q: Calculate pCd²+ at each of the given points in the titration of 40.00 mL of 0.0030 M Cd²+ with…

Q: Calculate the concentration (in M) of the complex product formed when Pb²+ was reacted with enough…

A: The balanced equation for the equilibrium reaction of Pb2+(aq) and EDTA4-(aq) is: Pb2+(aq) +…

Q: Which is NOT true about EDTA? a. EDTA acts as a complexing agent in compleximetric titrations b.…

A: EDTA(Ethylenediamine tetraacetic acid) is a polyprotic acid with 4 acid, -COOH groups and 2 amine,…

Q: Chromium (III) ion was complexed with EDTA and determined via back-titration. Given the following…

Q: Calculate pCd at each of the given points in the titration of 45.00 ml of 0.0010 M Cd with 0.0010 M…

A: Since you have posted a question with multiple sub-parts, we will solve first three subparts for…

Q: A 25.0 mL aliquot of 0.0660 M EDTA was added to a 46.0 mL solution containing an unknown…

A: Total concentration of EDTA = 0.0660 M Volume of EDTA = 25 mL EDTA reacts with V3+ and Ga3+

Q: The bismuth (AW 208.98) in 0.6805 g of an alloy was precipitated as BiOCl (FW 260.43) and separated…

A: Analysis of an unknown concentration of a sample can be done using the method of titration. This…

Q: CEC measurement did this calculation provide? C resulting from permanent charge on clays cal CEC at…

Q: 25.00 mL 0.01000 M Ni2+ is titrated with 0.01000 M EDTA in a solution buffered topH 5.0. Given that…

Q: The concentration of iron in a solution can be determined using UV?Vis spectrophotometry by reacting…

A: A question based in Beer-Lambert law, which is to be accomplished.

Q: 1. In this lab, FENCS" is being formed as a complex ion (complexation product) absorption peak at…

A: FeNCS2+ is a transition metal complex in which the oxidation state of iron is + 2. In the formation…

Q: According to the graph below, The ratio for One Metal is to how many LIGAND? (Write a whole number)…

A: We are given Absorbance versus Mole fraction of ligand plot for the Metal-Ligand complex. The given…

Q: Aluminium (III) reacts with the Chelating agent HL to give a complex AlL3 that is readily soluble in…

Q: A solution contains 3.0 mg of Fe?*/ liter. The Fe2* is converted into a complex with 1,10-phenan-…

A: It is an example of Lambert Beer law Here we need to find the absorptivity and molar absorptivity…

Q: Write the cell notation of the potentiometric set-up with SCE as the reference electrode. b)…

A: a) Anode II Cathode AgIAg+ IIHg2 cl2 IHg. cl-Anode 2Ag→2Ag+ +2e-CathodeHg2 cl2 +2e- →Hg+2cl- Solving…

Q: A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 48.2 mL of 0.0600 M EDTA. Titration of…

Q: A 20.0 ml. sample of 0.0200 M Cu buffered at pH 10.00 is titrated with 0.0300 M EDTA, Calculate pCu…

A: 20.0 mL sample of 0.0200 M Cu2+ is titrated with 0.0300 M EDTA. Let's first calculate the volume of…

Q: Is it posible to remove 99% of 1.0 μM CuY2- impurity (by reduction to solid Cu) from a 10.0 mM CoY2-…

A: We mainly have cobalt-EDTA solution (CoY2-) in which there is a little bit of copper impurity which…

Q: According to the graph below, The ratio for One Metal is to how many LIGAND? ( Write a whole number)…

A: The meet-point of the tangents drawn in the given spectrophotometric data meets the x-axis at 0.75.…

Q: A 25.00 mL aliquot of a solution containing Cu2+ and Fe3+ was titrated with 17.08 mL of 0.05095 M…

A: The titration is a method for the estimation of the concentration of ions. The titration that leads…

Q: A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 65.1 mL of 0.0400 M EDTA. Titration of…

A: Volume of EDTA = 65.1 mL Initial Molarity of EDTA = 0.04 M Initial moles of EDTA- Moles = Molarity…

Q: Solve the problem

A: Hello. Since your question has multiple parts, we will solve first question for you. If you want…

Q: A volume of 50.00 ml of 0.01800 mol L-1 EDTA solution was added to a solution containing 0.02550 g…

Q: Calculate pCd²+ at each of the given points in the titration of 50.00 mL of 0.0070 M Cd²+ with…

Q: Explain these question

A: As per our guidelines, we are allowed to answer the first three subparts for you. Kindly repost the…

Q: a) What is the equilibrium that influences the colour change of the Eriochrome Black T indicator?…

A: EDTA is ethylenediaminetetraacetic acid which is an indicator. It has 2 amino and 4 carboxyl groups.…

Q: A sample is analyzed for chloride by the Volhard method. Calculate the %KCl from the following data:…

A: Calculation of no. of mol of AgNO3: n=Molarity×Volume=0.1157 mol/L×35.00×10-3 L=4.0495×10-3 mol…

Q: Which of the following statements is false regarding the use of HCI in the UV-Vis experiment? O a.…

A: Spectroscopy is based on the interaction between light and matter. The principle of UV-VIS…

Q: using the An accurately weighed chelometric standard calcium carbonate of 200 mg was used to…

A: Disodium ethylenediaminetetraacetate, also known as disodium EDTA, has the following structure: In…

Q: The equivalence point is reached when 25.00 mL of 0.100 M EDTA is titrated with 25.00 mL of 0.100 M…

Q: a 10 ml sample containing fe3+ and cu2+ was diluted to 100.0 mL solution. A 20 mL aliquot required…

A: Answer is explained below.

Q: A cyanide solution with a volume of 13.87 mL was treated with 24.00 mL of Ni+ solution (containing…

A: Concentration of CN- can be determined from the amount of Ni2+ used in the titration of CN-.

Q: toothed ligands are not preferred in complexometric titrations?

A: Complexation Titrations are essentially Lewis acid-base reactions, in which an electron pair is…

Q: The cadmium and lead ions in a 50.00 mL sample required 40.09 mL of a 0.005000 M EDTA for titration.…

Q: Determination of water hardness using complexometric titration. During sample analysis (ppm…

A: Given: Determination of water hardness using complexometric titration. To determine EX…

Q: Calculate pCd²+ at each of the given points in the titration of 60.00 mL of 0.0060 M Cd²+ with…

Q: A 1.000-g sample containing bromide was dissolved in sufficient water to give 100.0 mL. A 50.00 mL…

A: To calculate the percentage of NaBr in the 1.000 g sample. It is given that Ni2+ ion produced from…

Q: The Cr metal was dissolved in HCl. The pH was suitably adjusted by adding ammnoniaammonium buffer…

A: To calculate the mass of Cr metal

Q: 1. Based on the following diagram: -2 Comman p range in nare H,CO, -3 HCO, co, 10 12 14 pH a) Locate…

A: a) From the graph given, the pKa1 and pKa2 are, pKa1 = 6.3 pKa2 = 10.3 These are given by the…

Q: Calculate the concentration of iron in the sample in parts per million.

Q: multidentate ligands impreferable for complexometric titrations (А тоже. false doe B

A: multidentate ligand are preferable for complexometric titration

Q: A 0.6006-g sample of Ni/Cu condenser tubing was dissolved in acid and diluted to 100 mL in a…

Q: In the titration of MgSO4.2H2O (2g per litre) against a 0.01 M solution of the disodium salt of…

A: Given 0.01 M solution of EDTA the reaction involving titration of MgSO4.2H2O and EDTA can be…

Q: A. Calgon conditioning can be done by____________________________. B. The colour of metal-EBT…

A: Since you've posted a question with multiple subparts, we will solve the first three subparts for…

Q: 25.00 mL 0.01000 M Ni2+ is titrated with 0.01000 M EDTA in a solution buffered to pH 5.0. Given that…

A: The stability constant is also known as the formation constant. It is the strength of the reactant…

Q: What is the purpose of an auxiliary complexing agent? O to attach to a metal ion through more than…

A: In EDTA tritration is to weakly bind to a metal, preventing the metal hydroxide from precipitating…

Q: A 15.0 mL sample of 0.0100 M Cu²+ buffered at pH 9.00 is titrated with 0.0300 M EDTA. Calculate…

A: Given: Volume of Cu2+ = 15.00 mL Concentration of Cu2+ = 0.0100 M pH=9.00 To Calculate pCu2+ for…

Q: When I was a boy, I watched Uncle Wilbur measure the iron content of runoff from his banana ranch.…

A: Beer–Lambert law A = ε l cA = absorbanceε = a constant ratio of (A) / (l) (c)l = length of cellc =…

Question

Chromium (III) ion was complexed with EDTA and determined via back-titration. Given the following data, compute for %CrCl3
(MM=158.35) in a 2.63 g sample.

Conc. of EDTA titrant: 0.0103 M
Volume used: 5.00 mL
Conc. of Zn2+ back titrant: 0.0112 M
Volume used: 1.32 mL

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions

Sketch a photometric titration curve for the titration of Sn2+ with MnO4 . What color radiation should be used for this titration? Explain.
Chromium (III) ion was complexed with EDTA and determined via back-titration. Given the following data, compute for %CrCl3 (MM=158.35) in a 2.63 g sample. Conc. of EDTA titrant: 0.0103 M Volume used: 5.00 mL Conc. of Zn2+ back titrant: 0.0112 M Volume used: 1.32 mL Answer: 0.221%
Chromel is an alloy composed of nickel, iron and chromium.A 0.6472 g sample was dissolved and diluted to 250 mL. When a50 mL aliquot of 0.05182 M EDTA was mixed with an equal volumeof the diluted sample and all the three ions were chelated, a 5.11 mLback titration with 0.06241 M copper (II) was required.The chromium in a second 50 mL aliquot was masked through theaddition of hexamethylenetetramine, titration of the Fe and Nirequired 36.28 mL of 0.05182 M EDTA.Iron and chromium were masked with pyrophosphate in a third50 mL aliquot and the nickel was titrated with 25.91 mL of theEDTA solution.Calculate the percentage of nickel, chromium and iron in thealloy.
A 1.000-g sample containing bromide was dissolved in sufficient water to give 100.0 mL. A 50.00 mL aliquot was measured and after acidification, silver nitrate was introduced to precipitate AgBr, which was filtered, washed, and then dissolved in an ammoniacal solution of potassium tetracyanonickelate(II): Ni(CN)42- + 2AgBr(s) → 2Ag(CN)2- + Ni2+ + 2Br-Nickel ion required 11.70 mL of 0.002146 M EDTAWhat is the percentage of NaBr (102.894) in the 1.000 g sample?
A sample is analyzed for chloride by the Volhard method. Calculate the %KCl from the following data: Wt of sample = 0.5000g; Vol of AgNO3 added = 35.00ml; M of AgNO3 = 0.1157; Vol of SCN- used for back titration = 14.71ml; M of SCN- = 0.08598; Atomic wts: Ag = 107.87, N = 14.00, Cl = 35.5, O = 16.00
The Cr metal was dissolved in HCl. The pH was suitably adjusted by adding ammnoniaammonium buffer solution and 15.00 mL of 0.01768 M EDTA were introduced. The excess reagent required a 4.30-mL back-titration with 0.008120 M Cu2+. Calculate mass of Cr metal.
25.00 mL 0.01000 M Ni2+ is titrated with 0.01000 M EDTA in a solution buffered topH 5.0. Given that the formation constant for the Ni-EDTA (NiY2–) chelate is4.2 x 1018 and the 4 value at pH 5.0 is 3.54 x 10–7. Explain briefly why EDTA is an important reagent used in complexometrictitrations.
What is the equivalence volume when 0.0500 M EDTA is titrated with 100.0 mL of 0.0500 M Mn+ buffered to a pH of 9.00?
A student withdraws 3.00Ml of supernate from a saturated solution of KHC8H4O4 at room temp (22C). This sample was titrated to the henolphthalein endpoint and 12.85mL of 0.0997 M NaOH was required A similare tiration was done at 22C for a saturated solution of KHP in 0.500 M KCl. The withgrawn supernant was 5.00mL. The volume of titrant (0.0997M NaOH) used was 11.75. a) calculate the % decrease in solubility by using this equation %decrease = [HC8H4O4]water - [HC8H4O4]sat'd KCl /[HC8H4O4]water
A solid containing tris was dissolved in water and brought to a total volume of 50.00 ml. A 10.00 ml aliquot of the solution was titrated with 0.09978 M HCl to a bromcresol green endpoint. The aliquot consumed 38.93 ml of titrant. Calculate the weight of tris in the original sample.
A 25.00 mL aliquot of a solution containing Cu2+ and Fe3+ was titrated with 17.08 mL of 0.05095 M EDTA. A second 25.00 mL aliquot of the Cu/Fe mixture was treated with NaF to form a stable iron-fluoride complex. This mixture was then titrated with EDTA and the endpoint volume was found to be 5.47 mL. Calculate the amounts of Cu2+ and Fe3+ in mg/L. Molar mass (g/mol): Fe = 55.85 and Cu = 63.55
A 1.000-g sample containing bromide was dissolved in sufficient water to give 100.0 mL. A 50.00 mL aliquot was measured and after acidification, silver nitrate was introduced to precipitate AgBr, which was filtered, washed, and then dissolved in an ammoniacal solution of potassium tetracyanonickelate(II): Ni(CN)42- + 2AgBr(s) → 2Ag(CN)2- + Ni2+ + 2Br- The liberated nickel ion required 11.70 mL of 0.002146 M EDTA The other 50.00 mL remaining solution was also analyzed for its Br- content by potentiometry using a metallic electrode of the second kind. Ecell recorded in running the solution using the potentiometric set-up was Ecell = 0.0286 V. (E0Ag/AgBr = 0.095 V) g) Compute for Eind. h) Compute pBr in the 50.00 mL aliquot. i) Compute for % NaBr ( in the potentiometric technique). j) Calculate the error between the obtained % NaBr fr the EDTA titration technique and the % NaBr from the potentiometric technique.