O CHEMICAL REACTIONS Solving moles-to-moles limiting reactant problems OO D 1/5 Solid aluminum (Al)and oxygen (0,) gas react to form solid aluminum oxide (Al,O,). Suppose you have 2.0 mol of Al and 7.0 mol of O, in a reactor. Suppose as much as possible of the Al reacts. How much will be left? Round your answer to the nearest 0.1 mol. Omol II

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Solving moles-to-moles limiting reactant problems
1/5
Solid aluminum (Al)and oxygen (02) gas react to form solid aluminum oxide (Al,03). Suppose you have 2.0 mol of Al and 7.0 mol of O, in a reactor.
Suppose as much as possible of the Al reacts. How much will be left? Round your answer to the nearest 0.1 mol.
I mol
Transcribed Image Text:ne File Edit View History Bookmarks Profiles Tab Window Help Watch Gilmore Girls | Netflix a Dashboard A ALEKS - Reyna Garcia O Psychology Research Sign-Up x T WPAL 101 233 Spring 2 A www-awu.aleks.com/alekscgi/x/lsl.exe/1o_u-lgNslkr7j8P3jH-IvdWKW_BBZZ16tTytly4Fcfu6zOtOf80MM9smRgOXk4zql8rHN-B4Sv7Er8YkAkkZH6IMU.. O ☆ Spotify Web Playe.. M Common Ethical D.. O CHEMICAL REACTIONS Solving moles-to-moles limiting reactant problems 1/5 Solid aluminum (Al)and oxygen (02) gas react to form solid aluminum oxide (Al,03). Suppose you have 2.0 mol of Al and 7.0 mol of O, in a reactor. Suppose as much as possible of the Al reacts. How much will be left? Round your answer to the nearest 0.1 mol. I mol
Expert Solution
Step 1

Solid aluminum(Al) and oxygenO2 gas reacts to form solid aluminum oxide(Al2O3).

The balanced equation is-

 2Al           +       1.5O2               Al2O3

Given = 2.0 mol of Al and 7.0 mol of O2.

For 2.0 mol of Al required moles of O2= 1.5

 

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