I need help with partC Engineering statics

Transcribed Image Text:I Review Part A Learning Goal: To apply the principle of moments and the principle of transmissibility. As shown, a rope is attached to al = 5.30m high shed that is to be relocated. A man pulls on the end of the rope at point A; the rope is attached to the shed at point B. (Figure 1) As the man pulls on the rope, it creates an angle 0 with the horizontal. The end of the rope is located at x = 3.30m from the shed and y = 2.00m off the ground. The man pulls on the rope with a force of magnitude F = 280N. What is MF., the contribution to the moment about point O made by the x component of the force F at point A? What is ME., the contribution to the moment about point O made by the y component of the force F at point A? What is the total moment M due to the force F about point O? Assume that moments acting counterclockwise about point O are positive whereas moments acting clockwise are negative. Express your answers, separated by commas, to three significant figures. • View Available Hint(s) MF, MF, M = 396,653,1050 N- m Submit Previous Answers v Correct Term 1: Correct answer is shown. Your answer 395.98 N · m was either rounded differently or used a different number of significant figures than required for this part. Figure < 1 of 3 > Term 2: Correct answer is shown. Your answer 653.36 N - m was either rounded differently or used a different number of significant figures than required for this part. В Term 3: Correct answer is shown. Your answer 1049.34 N · m was either rounded differently or used a different number of significant figures than required for this part. Part B Using the principle of transmissibility, the force F can be slid along its line of action from point A to any other point along its line of action. What points along the line of action of the force F would simplify the calculation of M, the magnitude of the total moment due to the force F about point O? (Figure 2) Check all that apply. • View Available Hint(s) B P Pearson Copyright © 2022 Pearson Education Inc. All rights reserved. | Terms of Use | Privacy Policy | Permissions | Contact Us |
Transcribed Image Text:I Review O G Learning Goal: To apply the principle of moments and the principle of transmissibility. Submit Previous Answers As shown, a rope is attached to al = 5.30m high shed that is to be relocated. A man pulls on the end of the rope at point A; the rope is attached to the shed at point B. (Figure 1) As the man pulls on the rope, it creates an angle 0 with the horizontal. The end of the rope is located at x = 3.30m from the shed and y = 2.00m off the ground. The man pulls on the rope with a force of magnitude F = 280N. v Correct The calculation of the moment M about point O due to the force F can be simplified by sliding the force along its line of action another point. Although either point B or E is a valid choice, here the moment M will be calculated by sliding the force F to point B. Part C Using the principle of transmissibility, the force F can be slid along its line of action to point B. At point B, the force F creates an angle o with the shed. (Figure 3) What is MF,, the contribution to the moment about point O made by the x component of the force F at point B? What is ME., the contribution to the moment about point O made by the y component of the force F at point B? What is the total moment M due to the force F about point O? Assume that moments acting counterclockwise about point O are positive whereas moments acting clockwise are negative. Figure < 1 of 3 Express your answers, separated by commas, to three significant figures. B • View Available Hint(s) Πν ΑΣφ ? vec MF. MF, M = N.m Submit Provide Feedback Next > P Pearson

Question

I need help with partC Engineering statics I ReviewPart ALearning Goal:To apply the principle of moments and the principle of transmissibility.As shown, a rope is attached to al = 5.30m high shed that is to berelocated. A man pulls on the end of the rope at point A; the rope is attachedto the shed at point B. (Figure 1) As the man pulls on the rope, it creates anangle 0 with the horizontal. The end of the rope is located at x = 3.30mfrom the shed and y = 2.00m off the ground. The man pulls on the ropewith a force of magnitude F = 280N.What is MF., the contribution to the moment about point O made by the x component of the force F at point A? What is ME., the contribution to the moment about point O madeby the y component of the force F at point A? What is the total moment M due to the force F about point O? Assume that moments acting counterclockwise about point O arepositive whereas moments acting clockwise are negative.Express your answers, separated by commas, to three significant figures.• View Available Hint(s)MF, MF, M = 396,653,1050 N- mSubmitPrevious Answersv CorrectTerm 1: Correct answer is shown. Your answer 395.98 N · m was either rounded differently or used a different number of significant figures than required for this part.Figure< 1 of 3 >Term 2: Correct answer is shown. Your answer 653.36 N - m was either rounded differently or used a different number of significant figures than required for this part.ВTerm 3: Correct answer is shown. Your answer 1049.34 N · m was either rounded differently or used a different number of significant figures than required for this part.Part BUsing the principle of transmissibility, the force F can be slid along its line of action from point A to any other point along its line of action. What points along the line of action of theforce F would simplify the calculation of M, the magnitude of the total moment due to the force F about point O? (Figure 2)Check all that apply.• View Available Hint(s)BP PearsonCopyright © 2022 Pearson Education Inc. All rights reserved. | Terms of Use | Privacy Policy | Permissions | Contact Us | I ReviewO GLearning Goal:To apply the principle of moments and the principle of transmissibility.SubmitPrevious AnswersAs shown, a rope is attached to al = 5.30m high shed that is to berelocated. A man pulls on the end of the rope at point A; the rope is attachedto the shed at point B. (Figure 1) As the man pulls on the rope, it creates anangle 0 with the horizontal. The end of the rope is located at x = 3.30mfrom the shed and y = 2.00m off the ground. The man pulls on the ropewith a force of magnitude F = 280N.v CorrectThe calculation of the moment M about point O due to the force F can be simplified by sliding the force along its line of action another point. Although either point B or Eis a valid choice, here the moment M will be calculated by sliding the force F to point B.Part CUsing the principle of transmissibility, the force F can be slid along its line of action to point B. At point B, the force F creates an angle o with the shed. (Figure 3) What is MF,, thecontribution to the moment about point O made by the x component of the force F at point B? What is ME., the contribution to the moment about point O made by the y componentof the force F at point B? What is the total moment M due to the force F about point O? Assume that moments acting counterclockwise about point O are positive whereasmoments acting clockwise are negative.Figure< 1 of 3Express your answers, separated by commas, to three significant figures.B• View Available Hint(s)Πν ΑΣφ?vecMF. MF, M =N.mSubmitProvide FeedbackNext >P Pearson

Accepted Answer

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