O3 O2 + 0 (fast, equilibrium) 03 +0 202 (slow)

Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter13: Fundamental Equilibrium Concepts
Section: Chapter Questions
Problem 4E: Is a system at equilibrium if the rate constants of the forward and reverse reactions are equal?
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Ozone decomposes to oxygen gas.

2O3(g) −→ 3O2(g)

A proposed mechanism for this decomposition is

What is the rate law derived from this mechanism?

O3
O2 + 0 (fast, equilibrium)
03 +0
202
(slow)
Transcribed Image Text:O3 O2 + 0 (fast, equilibrium) 03 +0 202 (slow)
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