of g(x), c, 5 and k) in the next section. For the following code segments below, count the operations andproduce a corresponding polynomial representation.f(x) =public static boolean isEmpty() {return head == null;}f(x)public static int num_occurrences(int n) {int count = 0;for(int i = 0; i < n; i++) {for(int j = 0; j < n; j++) {if( i == j ) continue;if(strings [i]count++;}}}return count;}strings[j]) {==f(2)public static void c(int n) {for(int a = 0; a < n; a++) {System.out.println( a}num_occurrences(n);}* a);f(x)public static boolean isPrime(int n) {if(n1) return false;==for(int i = 2; i kFor each of the polynomials above, pick a reference function (g(x)) and constants c,k such that theg(x) bounds f(x) in the most succinct terms possible for Big O. public static void main(String[] args) {for(int a = 0; a < n; a++) //nfoo(); //n}public static foo() {for(int a = 0; a < n; a++) //nSystem.out.println(a);}Log Exponent Rule: Consider the following logarithm a(x) = log2 X°. Note that we can rewritethis using the "log roll" as c * log2 X. Since constants are factored out during asymptotic analysis,you can simply drop the constant multiplier (which on a log is it's exponent).• Example f(x) = log2 X6f(x) becomes6 * log2 X, and O(log2 X)Log Base Rule: You may omit the base of the log and assume its base-2.Transitivity: if a < b< c, then a < c. Related to big , if a = 5x² + 3xand I'm trying to prove thata is less than or equal to (i.e, bounded by) x2, we would write5x? + 3x < c * x2 and find somepair of c, k such that this relationship holds. Using transitivity,5x? + 3x

f(x) = 1 (as it only has one basic process)

Answered: of g(x), c, 5 and k) in the next…

of g(x), c, 5 and k) in the next section. For the following code segments below, count the operations and produce a corresponding polynomial representation.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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