Question 9Of the choices below, choose the LARGEST set that contains ONLY sp2 hybridized atoms?H₂N 2H₂C5110H10 117CH₂1215H5, 9, 195, 7, 12, 145, 7, 12, 14 and 191, 5, 7, 12, 14 and 19O H₂C H13 1720=6916C 1918OH21Question 10 (What question in protein folding did Pauling's discovery of secondary structure address?Both alpha-helices and beta-sheets are very stable structures because of the phi-psi conformation ofpeptide main chain.OAlpha-helices and beta-sheets are often the first structures formed in protein folding, and they act asthe folding nucleus.Alpha-helices and beta-sheets show how a folded protein can satisfy the polar groups of the peptidemain chain through hydrogen bonding.Because alpha-helices and beta-sheets are such stable structures, they explained the why foldingwas a spontaneous reaction.

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Of the choices below, choose the LARGEST set that contains ONLY sp2 hybridized atoms? H₂C 10 11 CH₂ 15 H 5,9, 19 5, 7, 12, 14 5.7. 12, 14 and 19 1, 5, 7, 12, 14 and 19 N. 14 O H₂C 13 17 16 C H 20169 18 'OH 21 Question 10 ( What question in protein folding did Pauling's discovery of secondary structure address? Both alpha-helices and beta-sheets are very stable structures because of the phi-psi conformation of peptide main chain. Alpha-helices and beta-sheets are often the first structures formed in protein folding, and they act as the folding nucleus. O Alpha-helices and beta-sheets show how a folded protein can satisfy the polar groups of the peptide main chain through hydrogen bonding.

Of the choices below, choose the LARGEST set that contains ONLY sp2 hybridized atoms? H₂C 10 11 CH₂ 15 H 5,9, 19 5, 7, 12, 14 5.7. 12, 14 and 19 1, 5, 7, 12, 14 and 19 N. 14 O H₂C 13 17 16 C H 20169 18 'OH 21 Question 10 ( What question in protein folding did Pauling's discovery of secondary structure address? Both alpha-helices and beta-sheets are very stable structures because of the phi-psi conformation of peptide main chain. Alpha-helices and beta-sheets are often the first structures formed in protein folding, and they act as the folding nucleus. O Alpha-helices and beta-sheets show how a folded protein can satisfy the polar groups of the peptide main chain through hydrogen bonding.

Chemistry

9th Edition

ISBN:9781133611097

Author:Steven S. Zumdahl

Publisher:Steven S. Zumdahl

Chapter9: Covalent Bonding: Orbitals

Section: Chapter Questions

Problem 87CP: Consider the following computer-generated model of caffeine: Complete a Lewis structure for caffeine...

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Phosphoserine is a less-common amino acid. (a) Identify the hybridizations of atoms I through 5. (b) What are the approximate values of the bond angles A, B. C, and D? (c) What are the most polar bonds in the molecule?
Cinnamaldehyde ocaus naturally in cinnamon oil. (a) What is the most polar bond in the molecule? (b) How many bonds and how many bonds are there? (c) Is cis-trans isomerism possible? If so, draw the isomers of the molecule. (d) Give the hybridization of the C atoms in the molecule. (e) What are the values of the bond angles 1, 2, and 3 ?
Consider the following computer-generated model of caffeine: Complete a Lewis structure for caffeine in which all atoms have a formal charge of zero (as is typical with most organic compounds). How many C and N atoms are sp2 hybridized? How many C and N atoms are sp3 hybridized? sp hybridized? How many and bonds are there?
Draw a full Lewis structure for each following compound. Include lone pairs andnon-zero formal charges as necessary.a. HCN, hydrogen cyanideb. Si(OH)4, orthosilicic acid c. and d. are in photo attached. Look at cyclobutan-2,2-diol from d. Write the hybridizaOon of eitheroxygen atom (sp, sp2, or sp3). In Si(OH)4 (from question b.), write the hybridization of the silicon atom. Write compound in in this previous question that should exhibit a strong, sharp peak at 1712cm–1 in its IR spectrum.
What is the hybridization of the each of the labeled atoms for the potent neurotoxin (-)-gephyrotoxin? a. A = sp2, B = sp, C = sp2, D = sp3, E = sp3 b. A = sp2, B = sp, C = sp3, D = sp3, E = sp2 c. A = sp2, B = sp, C = sp2, D = sp3, E = sp2 d. A = sp2, B = sp, C = sp3, D = sp3, E = sp3 e. A = sp, B = sp, C = sp3, D = sp3, E = sp3
fill in the blanks Part a) 1st blank option ( sp, sp2, sp3, unhybridized) 2nd blank option ( linear, trigonal planar, trigonal pyramidal, tetrahedral) part b) 1st blank options ( 0,1,2,3,4,5,6) 2nd blank options ( 0,1,2,3,4,5,6) a) The carbon atoms in CH2=CH2 are best described as having a hybridization of ------ and the molecular geometry about the carbon atoms are best described as ------. b) A carbon atom that is sp2 hybridized will have ----- valence electrons occupying sp2 orbital and -----valence electrons occupying p orbitals.
What are the bond angles around heteroatoms and non-sp3 hybridised C atoms in C14H23NO ?
According to Werner's postulate, the sum of the primary and secondary valences in the compound hexaaminecobalt(III) oxalate is... A. 3 and 2 B. 3 and 6 C. 2 and 3 D. 2 and 6
The artificial sweetener Aspartame has the following structure: Simple organic compound like this one has a formal charge of zer (therefore, it is needed to add lone pairs). Note the benzene ring (-C6H6). To answer the questions below it can be good to draw the structure and account for electrons and bonds. How many C and O atoms exhibit sp3 hybridization? How many s bonds are in aspartame? How many pi bonds are in aspartame?
For the following descriptions of molecules, draw the Lewis structure (showing all atoms, lone pairs, formal changes) of the molecule and show all bond angles (assuming ideal VSEPR angles) 1) An organic compound with the molecular formula H3CNO2. C is sp2 hybridized, N is sp3 hybridized, one O is sp2 hybridized, while the second O is sp3 hybridized.
all of the orbital overlaps in NCO ‒---- Which of the following statements is TRUE? Select one: Pi bonds are stronger than sigma bonds. The sp2 hybridization scheme for carbon allows for the formation of two pi bonds. A carbon-carbon triple bond consists of one π bond. Pi bonds can hold 4 electrons: 2 above the bond axis, and 2 below the bond axis. A molecule with the VSEPR class AX4E2 will have a central atom that is sp3d2 hybridized.
Two isomers share the molecular formula C3H4. In Structure A two ofthe carbon atoms are sp hybridized and one carbon atom is sp3 hybridized. In Structure B, two of the carbon atoms are sp2 hybridized and one carbon atom is sphybridized. b)Draw “3D”-looking structures on paper, make a sketch of each of the isomers. (This should be a sketch of themolecules, not diagrams of overlapping orbitals!) Your drawing should show thecorrect molecular geometry around each carbon atom. [HINT: NEITHER of thesemolecules is planar!!! To draw them correctly, you will have to consider why!]