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Our method of calculating a 95 percent confidence interval for the mean u of a normal population, with known variance o2, is 1.960 1.960 Xn+ This method of creating an interval has the property that a single SRS of size n will provide an interval that will containing u with 0.95 probability. If five different individuals select 5 independent samples, each of size n, and obtain their resulting five interval estimates of 4, (i) what is the probability that u will belong to all five of them: (ii) None will contain µ? (iii) What is the probability that at least one of the intervals will contain µ? The following ^answers" have been proposed. (a) (i) (0.95)5, (ii) (0.95)5, (iii) (0.95)5. (b) (i) (0.05)5, (ii) 1– (0.05)5, (iii) (0.95)5, (c) (i) 1 – (0.05)5, (ii) (0.05)5, (iii) (0.95)5. (d) (i) (0.95)5, (ii) (0.05)5, (iii) 1 – (0.05)5. (e) None of the above. The correct answer is (a) (b) (d) (e) N/A (Select One)

Our method of calculating a 95 percent confidence interval for the mean u of a normal population, with known variance o2, is 1.960 1.960 Xn+ This method of creating an interval has the property that a single SRS of size n will provide an interval that will containing u with 0.95 probability. If five different individuals select 5 independent samples, each of size n, and obtain their resulting five interval estimates of 4, (i) what is the probability that u will belong to all five of them: (ii) None will contain µ? (iii) What is the probability that at least one of the intervals will contain µ? The following ^answers" have been proposed. (a) (i) (0.95)5, (ii) (0.95)5, (iii) (0.95)5. (b) (i) (0.05)5, (ii) 1– (0.05)5, (iii) (0.95)5, (c) (i) 1 – (0.05)5, (ii) (0.05)5, (iii) (0.95)5. (d) (i) (0.95)5, (ii) (0.05)5, (iii) 1 – (0.05)5. (e) None of the above. The correct answer is (a) (b) (d) (e) N/A (Select One)

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Our method of calculating a 95 percent confidence interval for the mean µ of a normal population, with known variance o2, is 1.960 1.960 Xn Xn + This method of creating an interval has the property that a single SRS of size n will provide an interval that will containing u with 0.95 probability. If five different individuals select 5 independent samples, each of size their resulting five interval estimates of 4, (i) what is the probability that u will belong to all five of them: (ii) None will contain µ? (iii) What is the probability that at least one of the intervals will contain u? and obtain п, The following``answers" have been proposed. (a) (i) (0.95)5, (ii) (0.95)5, (iii) (0.95)5. (b) (i) (0.05)5, (ii) 1– (0.05)5, (iii) (0.95)5, (c) (i) 1 – (0.05)5, (ii) (0.05)5, (iii) (0.95)5. (d) (i) (0.95)5, (ii) (0.05)5, (iii) 1 – (0.05)5. (e) None of the above. The correct answer is (a) (b) (c) (d) (e) N/A (Select One)
Transcribed Image Text:Our method of calculating a 95 percent confidence interval for the mean µ of a normal population, with known variance o2, is 1.960 1.960 Xn Xn + This method of creating an interval has the property that a single SRS of size n will provide an interval that will containing u with 0.95 probability. If five different individuals select 5 independent samples, each of size their resulting five interval estimates of 4, (i) what is the probability that u will belong to all five of them: (ii) None will contain µ? (iii) What is the probability that at least one of the intervals will contain u? and obtain п, The following``answers" have been proposed. (a) (i) (0.95)5, (ii) (0.95)5, (iii) (0.95)5. (b) (i) (0.05)5, (ii) 1– (0.05)5, (iii) (0.95)5, (c) (i) 1 – (0.05)5, (ii) (0.05)5, (iii) (0.95)5. (d) (i) (0.95)5, (ii) (0.05)5, (iii) 1 – (0.05)5. (e) None of the above. The correct answer is (a) (b) (c) (d) (e) N/A (Select One)
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