O ENTROPY AND FREE ENERGYCalculating dG from dH and dSA chemical engineer is studying the two reactions shown in the tablebelow.In each case, he fills a reaction vessel with some mixture of thereactants and products at a constant temperature of 143.0 °c and constanttotal pressure. Then, he measures the reaction enthalpy AH and reactionentropy as of the first reaction, and the reaction enthalpy AH andreaction free energy AG of the second reaction. The results of hismeasurements are shown in the table.Complete the table. That is, calculate AG for the first reaction and as forthe second. (Round your answer to zero decimal places.) Then, decidewhether, under the conditions the engineer has set up, the reaction isspontaneous, the reverse reaction is spontaneous, or neither forwardnor reverse reaction is spontaneous because the system is atequilibrium.P₁ (g) + 6C1₂ (8) 4PC1, (g)-6C(s) + 6H₂(g) + 30₂(g) → CH₁₂06(s)AH-1207. kJAS-2911.-AG=kJWhich is spontaneous?O this reactionO the reverse reactionOneitherΔΗ – – 1237. kJ-0-JKAS =AG = 0. kJ⠀Which is spontaneous?O this reactionO the reverse reactionOneither5200

∆G = ∆H - T∆SWhere,∆G = gibbs free energy∆H = reaction enthalpyT = temperature∆S = reaction entropy•…

P₁ (g) + 6C1₂ (g) 4PC1, (g) 6C(s) + 6H₂(g) + 30₂(g) → CH₁₂06(s) ΔΗ -1207. KJ AS = -2911. AG - KJ Which is spontaneous? O this reaction ΔΗ J - K AS= AG the reverse reaction -0--/- neither -1237. KJ 0. kJ Which is spontaneous? O this reaction the reverse reaction O neither X S

P₁ (g) + 6C1₂ (g) 4PC1, (g) 6C(s) + 6H₂(g) + 30₂(g) → CH₁₂06(s) ΔΗ -1207. KJ AS = -2911. AG - KJ Which is spontaneous? O this reaction ΔΗ J - K AS= AG the reverse reaction -0--/- neither -1237. KJ 0. kJ Which is spontaneous? O this reaction the reverse reaction O neither X S

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter12: Thermodynamic Processes And Thermochemistry

Section: Chapter Questions

Problem 78AP

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Question

O ENTROPY AND FREE ENERGY
Calculating dG from dH and dS
A chemical engineer is studying the two reactions shown in the table
below.
In each case, he fills a reaction vessel with some mixture of the
reactants and products at a constant temperature of 143.0 °c and constant
total pressure. Then, he measures the reaction enthalpy AH and reaction
entropy as of the first reaction, and the reaction enthalpy AH and
reaction free energy AG of the second reaction. The results of his
measurements are shown in the table.
Complete the table. That is, calculate AG for the first reaction and as for
the second. (Round your answer to zero decimal places.) Then, decide
whether, under the conditions the engineer has set up, the reaction is
spontaneous, the reverse reaction is spontaneous, or neither forward
nor reverse reaction is spontaneous because the system is at
equilibrium.
P₁ (g) + 6C1₂ (8) 4PC1, (g)
-
6C(s) + 6H₂(g) + 30₂(g) → CH₁₂06(s)
AH-1207. kJ
AS-2911.-
AG=kJ
Which is spontaneous?
O this reaction
O the reverse reaction
Oneither
ΔΗ – – 1237. kJ
-0-
J
K
AS =
AG = 0. kJ
⠀
Which is spontaneous?
O this reaction
O the reverse reaction
Oneither
5
2
00

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