P1.30 Rigid bar ABC shown in Figure Pl.30 is supported by a pin at bracket A and by tie rod (1). Tie rod (1) has a diameter of 5 mm, and it is supported by double-shear pin connections at Band D. The pin at bracket A is a single-shear connection. All pins are 7 mm in diameter. Assume a 600 mm, b 300 mm, h 450 mm, P = 900 N, and 0-55°. Determine the following: (a) the normal stress in rod (1) (b) the shear stress in pin B (c) the shear stress in pin A (1) %3D Please explain how this angle FIGURE PI.30 became 36.87 Solution Equilibrium: Using the FBD shown, calculate the reaction forces that act on rigid bar ABC. EM, = F, sin(36.87°)X600 mm) 36.87 -(900 N)sin (55°)(900 mm) = 0 E -1 843 092 N

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter2: Axially Loaded Members
Section: Chapter Questions
Problem 2.6.13P: A plastic bar of rectangular cross section (ft = 1.5 in. and h = 3 in.) fits snugly between rigid...
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Please clarify how this angle became 36.87 that you referred to
P1.30 Rigid bar ABC shown in Figure Pl.30 is
supported by a pin at bracket A and by tie rod (1).
Tie rod (1) has a diameter of 5 mm, and it is
supported by double-shear pin connections at Band
D. The pin at bracket Ais a single-shear
connection. All pins are 7 mm in diameter.
Assume a = 600 mm, b 300 mm, h 450 mm, P
= 900 N, and 0= 55°. Determine the following:
(a) the normal stress in rod (1)
(b) the shear stress in pin B
(c) the shear stress in pin A
(1)
Please explain how this angle
became 36.87
FIGURE PI.30
Solution
Equilibrium: Using the FBD shown, calculate
the reaction forces that act on rigid bar ABC.
EM, = F, sin(36.87°)X600 mm)
36,87
-(900 N)sin (55°)(900 mm) = 0
. F = 1,843.092 N
Transcribed Image Text:P1.30 Rigid bar ABC shown in Figure Pl.30 is supported by a pin at bracket A and by tie rod (1). Tie rod (1) has a diameter of 5 mm, and it is supported by double-shear pin connections at Band D. The pin at bracket Ais a single-shear connection. All pins are 7 mm in diameter. Assume a = 600 mm, b 300 mm, h 450 mm, P = 900 N, and 0= 55°. Determine the following: (a) the normal stress in rod (1) (b) the shear stress in pin B (c) the shear stress in pin A (1) Please explain how this angle became 36.87 FIGURE PI.30 Solution Equilibrium: Using the FBD shown, calculate the reaction forces that act on rigid bar ABC. EM, = F, sin(36.87°)X600 mm) 36,87 -(900 N)sin (55°)(900 mm) = 0 . F = 1,843.092 N
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