Part 2 Table: Results of sodium bicarbonate addition to acetic acid. Run 1 Run 2 Run 3 Run 4 Run 5 Run 6 Volume of Acetic 1 Acid, C2H402 5% v/v 5% v/v 5%v/v 5% v/v 5% v/v 5% v/v Mass of Sodium 2 Bicarbonate, NaHCOз 0.626 g 1.203 g 2.473 g 4.839 g 7.228 g 9.628 g Mass of eguipment

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
icon
Related questions
Question

Fill out the table 

Part 2 Table: Results of sodium bicarbonate addition to acetic acid.
Run 1
Run 2
Run 3
Run 4
Run 5
Run 6
Volume of Acetic
1
Acid, C2H402
5% v/v
5% v/v
5%v/v
5% v/v
5% v/v
5% v/v
Mass of Sodium
Bicarbonate,
NaHCO3
0.626 g
1.203 g
2.473 g
4.839 g
7.228 g
9.628 g
Mass of equipment
3
& reaction mixture
before reaction
138.495g
135.169 g
132.161 g
152.002 g
155.488 g
153.896 g
Mass of equipment
and reaction
4
mixture after
138.315g
134.159 g
131.037 g
150.188 g
153.676 g
152.103 g
reaction
Mass of CO2 (g)
evolved during the
reaction (4 - 5)
0.18g
1.01g
1.124g
1.814g
1.812g
1.793g
6
Moles of CO2
0.00409
Moles of NaHCO3
7
that reacted
Mass of NaHCO3
8
that reacted
% NaHCO3 that
9
reacted (8 / 2) x
100)
1,768 words
Transcribed Image Text:Part 2 Table: Results of sodium bicarbonate addition to acetic acid. Run 1 Run 2 Run 3 Run 4 Run 5 Run 6 Volume of Acetic 1 Acid, C2H402 5% v/v 5% v/v 5%v/v 5% v/v 5% v/v 5% v/v Mass of Sodium Bicarbonate, NaHCO3 0.626 g 1.203 g 2.473 g 4.839 g 7.228 g 9.628 g Mass of equipment 3 & reaction mixture before reaction 138.495g 135.169 g 132.161 g 152.002 g 155.488 g 153.896 g Mass of equipment and reaction 4 mixture after 138.315g 134.159 g 131.037 g 150.188 g 153.676 g 152.103 g reaction Mass of CO2 (g) evolved during the reaction (4 - 5) 0.18g 1.01g 1.124g 1.814g 1.812g 1.793g 6 Moles of CO2 0.00409 Moles of NaHCO3 7 that reacted Mass of NaHCO3 8 that reacted % NaHCO3 that 9 reacted (8 / 2) x 100) 1,768 words
Expert Solution
Step 1

The required reaction is :

CH3COOH + NaHCO3 = CH3COONa + H2O + CO2

equal moles of sodium bicarbonate reacts with acetic acid.

                  CH3COOH + NaHCO3 = CH3COONa + H2O + CO2Initial          5% v/v             0.626Change           -x               -x               +x                             +xEquilibrium  5%-x            0.626-x         x                                   xtherefore equilibrium concentration of bicarbonate =0.626-[CO2]     or, bicarbonate reacted =[CO2]

 

 

 

trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer
Knowledge Booster
Matter
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY