Part B The integrated rate law allows chemists to predict the reactant concentration after a certain amount of time, or the time it would take for a certain concentration to be reached. What is the rate constant of a first-order reaction that takes 8.90 minutes for the reactant concentration to drop to half of its initial value? • View Available Hint(s) The integrated rate law for a first-order reaction is: [A] = [A]oe-kt Now say we are particularly interested in the time it would take for the concentration to become one-half of its inital value. Then Πνα ΑΣφ we could substitute Alo for [A] and rearrange the equation to: [A], 0.693 579 min- t/2 = This equation caculates the time required for the reactant concentration to drop to half its initial value. In other words, it calculates the half-life. Submit Previous Answers X Incorrect; Try Again; attempts remaining Part C A certain first-order reaction has a rate constant of 2.60x10-3 s1. How long will it take for the reactant concentration to drop to - of its initial value? • View Available Hint(s)

Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter14: Chemical Kinetics: The Rates Of Chemical Reactions
Section: Chapter Questions
Problem 6PS: 6. Phenyl acetate, an ester, reacts with water according to the equation The data in the table were...
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part b and c please

Part B
The integrated rate law allows chemists to predict the reactant
concentration after a certain amount of time, or the time it would
What is the rate constant of a first-order reaction that takes 8.90 minutes for the reactant concentration to drop to half of its initial value?
take for a certain concentration to be reached.
• View Available Hint(s)
The integrated rate law for a first-order reaction is:
[A] = [A]oe-kt
Now say we are particularly interested in the time it would take
ΑΣφ
for the concentration to become one-half of its inital value. Then
we could substitute
[A]o
for [A and rearrange the equation to:
2
579
min-1
0.693
t1/2 =
k
This equation caculates the time required for the reactant
concentration to drop to half its initial value. In other words, it
Submit
Previous Answers
calculates the half-life.
X Incorrect; Try Again; 4 attempts remaining
Part C
A certain first-order reaction has a rate constant of 2.60x10-3 s-. How long will it take for the reactant concentration to drop to - of its initial value?
• View Available Hint(s)
ΑΣφ
?
Transcribed Image Text:Part B The integrated rate law allows chemists to predict the reactant concentration after a certain amount of time, or the time it would What is the rate constant of a first-order reaction that takes 8.90 minutes for the reactant concentration to drop to half of its initial value? take for a certain concentration to be reached. • View Available Hint(s) The integrated rate law for a first-order reaction is: [A] = [A]oe-kt Now say we are particularly interested in the time it would take ΑΣφ for the concentration to become one-half of its inital value. Then we could substitute [A]o for [A and rearrange the equation to: 2 579 min-1 0.693 t1/2 = k This equation caculates the time required for the reactant concentration to drop to half its initial value. In other words, it Submit Previous Answers calculates the half-life. X Incorrect; Try Again; 4 attempts remaining Part C A certain first-order reaction has a rate constant of 2.60x10-3 s-. How long will it take for the reactant concentration to drop to - of its initial value? • View Available Hint(s) ΑΣφ ?
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